I think it would be $77.00
Answer: 0.9730
Step-by-step explanation:
Let A be the event of the answer being correct and B be the event of the knew the answer.
Given: 


If it is given that the answer is correct , then the probability that he guess the answer 
By Bayes theorem , we have


Hence, the student correctly answers a question, the probability that the student really knew the correct answer is 0.9730.
Step-by-step explanation:
9x - 2x = 8 + 5
7x = 13
x =13÷7
x = 1.8571
approximately = 1.86
I think this is it
Answer:
No real solutions
Step-by-step explanation:
Divide both sides by 3
3x^3/3=-54/3
x^2=-18
Take square root
x=±√−18
The answer is <span>√x + √y = √c </span>
<span>=> 1/(2√x) + 1/(2√y) dy/dx = 0 </span>
<span>=> dy/dx = - √y/√x </span>
<span>Let (x', y') be any point on the curve </span>
<span>=> equation of the tangent at that point is </span>
<span>y - y' = - (√y'/√x') (x - x') </span>
<span>x-intercept of this tangent is obtained by plugging y = 0 </span>
<span>=> 0 - y' = - (√y'/√x') (x - x') </span>
<span>=> x = √(x'y') + x' </span>
<span>y-intercept of the tangent is obtained by plugging x = 0 </span>
<span>=> y - y' = - (√y'/√x') (0 - x') </span>
<span>=> y = y' + √(x'y') </span>
<span>Sum of the x and y intercepts </span>
<span>= √(x'y') + x' + y' + √(x'y') </span>
<span>= (√x' + √y')^2 </span>
<span>= (√c)^2 (because (x', y') is on the curve => √x' + √y' = √c) </span>
<span>= c. hope this helps :D</span>