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castortr0y [4]
3 years ago
9

What is the factor of 12 but not the multiple of 3

Mathematics
1 answer:
algol133 years ago
7 0
The factor of 12 is 4
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barb ate six cheeseburgers in the last four months. How many do you perdict she will eat in two years?
hichkok12 [17]
36 :))) 4 x 3 = 12... 6 x 3 = 18 x 2 = 36!!
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5 0
3 years ago
What is the surface area of a square pyramid with a base length of 8 and a height of 12
Alexxx [7]

Answer:

256

Step-by-step explanation:

b^2 + 2bl

8^2 + 2(8)(12)

64 + 16(12)

64 + 192

= 256

6 0
3 years ago
Glenn spends 105 minutes exercising every day. He spends 3 fifths of the time running. How much time dose Glenn spend running?
lozanna [386]

Answer: 63 mins

Step-by-step explanation:

105(\frac{3}{5})=63

7 0
3 years ago
Mark's school is selling tickets to the annual dance competition. On the first day of ticket sales the school sold 4 senior tick
erica [24]

The cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

<em><u>Solution:</u></em>

Let "a" be the price of each senior ticket

Let "b" be the price of each child ticket

<em><u>On the first day of ticket sales the school sold 4 senior tickets and 4 child tickets for a to total of 68</u></em>

Thus a equation is framed as:

4 senior tickets x price of each senior ticket + 4 child tickets x price of each child ticket = 68

4 \times a + 4 \times b = 68

4a + 4b = 68 ---------- eqn 1

<em><u>The school took in 120 on the second day by selling 12 senior tickets and 5 child tickets</u></em>

Similarly, we frame a equation as:

12 \times a + 5 \times b = 120

12a + 5b = 120 ---------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 3</u></em>

12a + 12b = 204 -------- eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

12a + 12b = 204

12a + 5b = 120

( - ) --------------

7b = 84

b = 12

<em><u>Substitute b = 12 in eqn 1</u></em>

4a + 4(12) = 68

4a + 48 = 68

4a = 20

a = 5

Thus cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

4 0
2 years ago
3. In the figure below, E is on AD and C is on BD. The dimensions given are in meters. What is the length, in meters, of CD?
damaskus [11]

Answer:

C. 3,960

Step-by-step explanation:

∆ADB ~ ∆EDC. Therefore,

\frac{AB}{EC} = \frac{DB}{DC}

\frac{2,000}{1,200} = \frac{2,640 + x}{x} (substitution)

Solve for x

\frac{5}{3} = \frac{2,640 + x}{x}

Cross multiply

5*x = 3(2,640 + x)

5x = 7,920 + 3x

5x - 3x = 7,920

2x = 7,920

x = 7,920/2

x = 3,960 meters

7 0
2 years ago
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