Answer:
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Explanation:
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Answer:
<em>The programming language is not stated; however, I'll answer using Python programming language (</em><em>Se</em><em>e attachment</em><em> </em><em>for</em><em> </em><em>proper </em><em>for</em><em>mat</em><em>)</em>
tuition = 10000
rate = 0.04
for i in range(1,15):
tuition = tuition + tuition * rate
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
Explanation:
<em>The first 2 lines initializes tuition and rate to 10000 and 0.04 respectively</em>
tuition = 10000
rate = 0.04
<em>The next line iterates from year 1 to year 14</em>
for i in range(1,15):
<em>This line calculates the tuition for each year</em>
tuition = tuition + tuition * rate
<em>The next 3 lines prints the tuition for year 1 to year 10</em>
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
<em>The next 3 lines prints the tuition at the 4th year after year 10 (i.e. year 14)</em>
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
Explanation:
calculators work by processing information in binary form. We're used to thinking of numbers in our normal base-ten system, in which there are ten digits to work with: 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. The binary number system is a base-two system, which means there are only two digits to work with: 0 and 1. Thus, when you input numbers into a calculator, the integrated circuit converts those numbers to binary strings of 0s and 1s.
The integrated circuits then use those strings of 0s and 1s to turn transistors on and off with electricity to perform the desired calculations. Since there are only two options in a binary system (0 or 1), these can easily be represented by turning transistors on and off, since on and off easily represent the binary option
Once a calculation has been completed, the answer in binary form is then converted back to our normal base-ten system and displayed on the calculator's display screen.