To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
Answer:
I think that they all have fairness in the class assignment process.
I think this because of the way that more people take art club than art class,
Step-by-step explanation:
I got X=11
Minus 7x on both sides
The equation the becomes :
-2x +179=157
Subtract 179 from both sides
Equation now is:
-2x= -22
Divide -2 on both sides
X= 11
(g₀f)(x)=g(f(x))
=g(2x-2)
=5(2x-2)^2-3
=5(4x^2-8x+4)-3
=20x^2-40x+17
