All categories

3 years ago

Find the simple interned earned in savings account that pay 5% interest if $500 is deposited for 4 years

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

4 0

The answer is 100 dollars.

You might be interested in

What is 1/7 As a decimal?<br><br> Give your answer rounded to 2 decimal places.

PIT_PIT [208]

Answer:

0.14

Step-by-step explanation:

1/7 = 0.1428571429.......

round to two decimal places so se look at the 4 which is the second decimal place, and then we see that the number to the right of it is less than 5 and therefore we round down to 4 and not 5.

:) hope this helps, please mark as brainliest!

4 0

3 years ago

Does anybody know how to solve this please with work along with each one? Thank you

Allushta [10]

What grade are u in.

5 0

3 years ago

If g(x)=f(x+1), then g(x) translates the function f(x) 1 unit _[blank]_.

galina1969 [7]

answer: right

reason: because you are talking about the x axis so if you go left that would be a negative and you cant go up and down bc that's the y axis so the only way to go is right

hope this helped

4 0

3 years ago

Can anyone help with this ??

ANEK [815]

Oof why do you think of the most important things to do in the future and the other is a great way to get the best out of the way and I have to say that I am not a fan of 45372

4 0

3 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago