The smallest of two integers is 61
Step-by-step explanation:
Let x be the smaller integer
Then the next integer will be:
x+1
According to given statement that the sum of both is 123

Subtracting 1 from both sides

Dividing both sides by 2

The smallest of two integers is 61
Keywords: Linear equations, Variables
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You use the quadratic formula:
2x {}^{2} - 3x = 5
2x {}^{2} - 3x - 5 = 0
x = \frac{3 + - \sqrt{9 -4(2)( - 5)}}{2 \times 2}
x = \frac{3 + - \sqrt{49} }{4}
x = \frac{3 + 7}{4} \: and \: x = \frac{3 - 7}{4}
x = \frac{5}{2} \: and \: x = - 1
Equation 1 ==> y - x = -13
Equation 2 ==> -4x + 3y = -51
3(y - x) = 3(-13)
Equation 3 ==> 3y - 3x = -39
Equation 2 - 3
= (3y - 3y) + ( -4x - (-3x) ) = -51 - (-39)
-x = -12
x = 12
Substitude x into equation 1
y - 12 = -13
y = -1
Answer:I think it's -23.72
Step-by-step explanation:Step 1: Reduce the fraction
Step 2: Multiply
Step 3: Calculate
step 4: solution