The graph of a linear relationship is shown. Which equation best represents the relationship between x and y in the graph

Mathematics

1 answer:

Finger [1]2 years ago

8 0

Answer:

B. y = -3/4x + 5/2

Step-by-step explanation:

Take two points from the graph, let's use (-2, 4) and (2, 1):

Find slope:

m = (y₂ - y₁) / (x₂ - x₁)

= (1 - 4) / (2 - (-2))

= -3/4

Find y-intercept using slope above and anyone point:

y = mx + b

(1) = -3/4(2) + b

1 = -3/2 + b

b = 1 + 3/2

b = 5/2

Equation of line using m and b above:

y = mx + b

y = -3/4x + 5/2

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Is -5/12 and irrational or rational

oksian1 [2.3K]

Answer:

Rational.

Step-by-step explanation:

Since it can be put into a fraction, negative or positive it is clearly rational. Irrational numbers are numbers we can never know the true value because they repeat forever (pi for example)

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2 years ago

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Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.