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Ludmilka [50]
3 years ago
11

Antoinette solves the linear equation 3(x-3)+2x+9=2x+2(x-1)

Mathematics
1 answer:
xeze [42]3 years ago
8 0
Hope this worked :3

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Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
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Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

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How does the number of zeros in the product of 8 and 5000 compare to the number of zeroes in the factor
almond37 [142]
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What are the coordinates of the point on the directed line segment from (3,3) to
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Answer:

3,5

Step-by-step explanation:

the answer is 3,5

I hope this helps

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