Answer:
- The angle ∠2 = 4x = 4(36°) = 144°
Step-by-step explanation:
We know that when two lines meet or intersect, we get a linear pair of angles.
Linear pairs are basically two adjacent angles that form a line.
The measure of two adjacent angles forming a straight line is 180, meaning they are supplementary.
We are given that <1 and <2 forms a linear pair, and
m∠1 = 4m∠2
It means the angle ∠1 is 4 times the measure of angle ∠2.
Let the angle ∠1 be = x
As the angle 1 is 4 times the measure of angle ∠2, so
The angle 2 will be = 4x
As <1 and <2 forms a linear pair, thus the measure of the sum of <1 and <2 will be 180°, so
x + 4x = 180
5x = 180
divide both sides by 5
5x/5 = 180/5
x = 36°
Therefore,
- The angle ∠2 = 4x = 4(36°) = 144°
Answer:
2/8
Step-by-step explanation:
freshman=4/8
1/8 soph 1/8 jr
add all together u get 6/8
the rest is seniors so its 2/8
Answer:
Given that an article suggests
that a Poisson process can be used to represent the occurrence of
structural loads over time. Suppose the mean time between occurrences of
loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a
4-year period? c). How long must a time period be so that the probability of no loads
occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a
4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads
occurring during that period is at most 0.3 is given by: 3.3 years
Step-by-step explanation:
She gets to the library at 5:30. Half an hour is equal to 30 minutes, and if she leaves at 5:00, she will be there in thirty minutes.
Here is your answer:
Since their no zeros (0) here's your answer:
6.174798604×10^9
