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tigry1 [53]
3 years ago
11

Six equilateral triangles are connected to create a regular hexagon. The area of the hexagon is 24a2 – 18 square units. Which is

an equivalent expression for the area of the hexagon based on the area of a triangle?
6(4a2 – 3)
6(8a2 – 9)
6a(12a – 9)
6a(18a – 12)
Mathematics
1 answer:
shusha [124]3 years ago
3 0
It would be 6(4a2 - 3)
you would factor out just the 6 because the 18 doesn’t a a term with it like 34a2 does. then just divide normally to get ur answer 6(4a2 - 3)
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rusak2 [61]

Answer:

L is not valid.

Step-by-step explanation:

For any triangle, the sum of the two legs must be greater than the hypotenuse. Otherwise the two legs would not be long enough to touch.

7 0
2 years ago
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Plz answer it fast...
Sveta_85 [38]

Answer:

Rs 2163.20.

Step-by-step explanation:

The formula for this is

A = P(1 + r)^t     where P is the amount invested, r = the rate (as a decimal) and t = the number of years.

So for rs 2000 we have:

A = 2000(1 + 0.04)^2 = Rs 2163.20

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3 years ago
Can u please help me on part C? The arcs in the photo at the right appear to be paths of stars rotating about the North Star. To
Natasha_Volkova [10]

no i would if i could but sadly i dont know the answer.

5 0
2 years ago
a sailmaker is designing a mainsail for a newly constructed sailboat. the mainsail foot is 13 feet long, the luff is 10 feet lon
Vikentia [17]
  • (A) The mainsail foot is 13 feet long, the luff is 10 feet long, the leach is 6.93 feet long, and the mainsail area is 64.85 ft².
  • (B) The mainsail foot is 13 feet long, the luff is 10 feet long, and the luff forms a 50° angle with the leach at the head, requiring the length of the leach and the area of the mainsail.

<h3>What exactly is sines law?</h3>
  • The law of sines refers to the ratio of a triangle's side length to the sine of the opposite angle, which is the same for all sides.
  • SinA/a = SinB/b = SinC/c
  • Where A, B, and C represent the triangle's angle and a,b, and c represent the opposite sides of the triangle's angle.

So, Part A:

By employing the sines law,

  • SinA/10 = SinB/13
  • SinA/10 = Sin50/13
  • A = 36.10
  • C = 180-(180-36.10)
  • C = 93.90

So,

  • Sin36.10 / a = Sin50/ b = Sin93.90/c
  • Sin36.10 / 10 = Sin50/ 13 = Sin93.90/c
  • c = Sin93.90 × 13 ÷ Sin50
  • c = 16.93 ft

Now, Part B:

Area of the mainsail:

  • = 1/2 × abSinC
  • = 1/2 × 10 × 13 × Sin93.90
  • =  64.85

Therefore, the answers to both parts are:

  • (A) The mainsail foot is 13 feet long, the luff is 10 feet long, the leach is 6.93 feet long, and the mainsail area is 64.85 ft².
  • (B) The mainsail foot is 13 feet long, the luff is 10 feet long, and the luff forms a 50° angle with the leach at the head, requiring the length of the leach and the area of the mainsail.

Know more about sines law here:

brainly.com/question/27174058

#SPJ4

The complete question is given below:

A sailmaker is designing a mainsail for a newly constructed sailboat. The mainsail foot is 13 feet long, the luff is 10 feet long, and the luff makes a 50° angle at the head with the leach.

Part A: Determine the length of the leach.

Part B: Find the area of the mainsail.

PLS HELP :) 50 POINTS!!!

6 0
1 year ago
Help. I just want to be done with HW.
Reil [10]

Answer: I FEEL YA :(

1) 4/15

2) 1/21

3) 1/13

4) 1/4

5) 1/5

6) 1/2

7) 1/4

8) 5/14

9) 4/9

10) 1/6

i'm pretty sure these are right, hope this helped! :)

6 0
3 years ago
Read 2 more answers
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