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tigry1 [53]
3 years ago
11

Six equilateral triangles are connected to create a regular hexagon. The area of the hexagon is 24a2 – 18 square units. Which is

an equivalent expression for the area of the hexagon based on the area of a triangle?
6(4a2 – 3)
6(8a2 – 9)
6a(12a – 9)
6a(18a – 12)
Mathematics
1 answer:
shusha [124]3 years ago
3 0
It would be 6(4a2 - 3)
you would factor out just the 6 because the 18 doesn’t a a term with it like 34a2 does. then just divide normally to get ur answer 6(4a2 - 3)
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Can someone help pls
cestrela7 [59]

1. \frac{6}{12}  =  \frac{1}{2}

2. \frac{24}{30}  =  \frac{4}{5}

3. \frac{9}{36}  =  \frac{1}{4}

4. \frac{15}{24}  =  \frac{5}{8}

5. \frac{9}{18}  =  \frac{1}{2}

6. \frac{12}{9}  =  \frac{4}{3}

7. \frac{5}{10}  =  \frac{1}{2}

8. \frac{24}{32}  =  \frac{3}{4}

9. \frac{10}{35}  =  \frac{2}{7}

10. \frac{18}{90}  =  \frac{2}{10}  =  \frac{1}{5}

11. \frac{8}{32}  =  \frac{1}{4}

12. \frac{18}{14}  =  \frac{9}{7}

13. \frac{2}{6}  =  \frac{1}{3}

14. \frac{12}{18}  =  \frac{6}{8}  =  \frac{3}{4}

15. \frac{24}{9}  =  \frac{8}{3}

16. \frac{7}{28}  =  \frac{1}{4}

17. \frac{6}{21}  =  \frac{2}{7}

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