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const2013 [10]
3 years ago
13

Four more than the quotient of a number and 3 is 9

Mathematics
1 answer:
barxatty [35]3 years ago
4 0

The algebraic expression of "Four more than the quotient of a number and 3 is 9" is \frac{x}{3}+4=9

The value of x=15

Step-by-step explanation:

We need to express "Four more than the quotient of a number and 3 is 9" as algebraic expression.

Let the number = x

Solving:

quotient of a number and 3: \frac{x}{3}

Four more than the quotient of a number and 3: \frac{x}{3}+4

Four more than the quotient of a number and 3 is 9: \frac{x}{3}+4=9

Now, finding value of x:

\frac{x}{3}+4=9\\Adding\,\,-4\,\,on\,\,both\,\,sides:\\\frac{x}{3}+4-4=9-4\\\frac{x}{3}=5\\Multiply\,\,both\,\,sides\,\,by\,\,3:\\x=5*3\\x=15

So, value of x = 15

Keywords: Algebraic expression

Learn more about algebraic expression at:

  • brainly.com/question/1600376
  • brainly.com/question/1617787
  • brainly.com/question/9720317

#learnwithBrainly

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What is 20/45 simplified
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A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 33.9 wee
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Answer:

P(35.3 < M < 35.4) = 0.0040.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 33.9, \sigma = 6.7, n = 119, s = \frac{6.7}{\sqrt{119}} = 0.6142

Find the probability that a single randomly selected value is between 35.3 and 35.4

This is the pvalue of Z when X = 35.4 subtracted by the pvalue of Z when X = 35.3. So

X = 35.4

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{35.4 - 33.9}{0.6142}

Z = 2.44

Z = 2.44 has a pvalue of 0.9927

X = 35.3

Z = \frac{X - \mu}{s}

Z = \frac{35.3 - 33.9}{0.6142}

Z = 2.28

Z = 2.28 has a pvalue of 0.9887

0.9927 - 0.9887 = 0.0040

So the answer is:

P(35.3 < M < 35.4) = 0.0040.

4 0
3 years ago
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