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lana [24]
3 years ago
13

Someone get me the answers ASAP!! thank you

Mathematics
1 answer:
elena-s [515]3 years ago
3 0
It's 11 because 6+5=11 other words it means it's 11 squares away

You might be interested in
The area of a square is 64n36 square units. What is the side length of one side of the square?
storchak [24]

Answer:

Step-by-step explanation:

Since the formula for the area of a square is A = x^2, where x is the side length, x = √A.

If A = 64 square units, the side length is √64 units (8 units)

If A = 36 square units, that length is √36 units (6 units)

5 0
3 years ago
What else would need to be congruent to show that ABC=DEF by SAS?
KonstantinChe [14]

Answer:

A

Step-by-step explanation:

SAS = side-angle-side

This means that, in order to prove that the triangles are congruent, they must have two congruent sides with the angle between them to the same.

We know that sides AB, ED, AC, and DF are all congruent as they all have a single mark through them. From this, you can conclude that the triangles already share two sides. All we need now is the angles in between to be congruent. This means that angle A and angle D need to be congruent.

I hope this helps!

7 0
3 years ago
Find the value of the angle θ rounded to 1 DP.
kogti [31]

Answer:

Step-by-step explanation:

Sin 21 = \frac{opposite side}{hypotenuse}

Sin 21 = \frac{BC}{15}

0.3583 = \frac{BC}{15}

0.3583*15 = BC

BC = 5.3745 = 5.37 m

Tan ∅ = \frac{opposite side}{adjacent side}

Tan ∅ = \frac{4}{5.37}= 0.7448

∅ = tan⁻¹ (0.7448) = 36.67 = 36.7

5 0
2 years ago
Could anyone please help?​
natima [27]

Answer:

b+3a

Step-by-step explanation:

MN=AN+AM

AN=0.5*AB

AB=OA+OB=4a+2b

AN=2a+b

AM=OA-OM=4a-3a=a

MN=2a+b+a=3a+b

3 0
3 years ago
Read 2 more answers
If you are reading this please help!!!!
Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

                          =-12 x^{5}+21 x^{2}

2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

                              =12 x^2+8x-15

3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

3 0
3 years ago
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