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omeli [17]
2 years ago
14

Solve the equation 14 = 14n

Mathematics
1 answer:
user100 [1]2 years ago
6 0

Answer: I think the answer is n = 1.

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Given that cos(theta) = 8/17 and that theta lies in Quadrant IV, what is the exact value of sin 2(theta)?
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Answer:    -\frac{240}{289}

=========================================================

Explanation:

Use the pythagorean trig identity \sin^2(\theta)+\cos^2(\theta) = 1 and plug in the fact that \cos(\theta) = \frac{8}{17}\\\\

Isolating sine leads to \sin(\theta) = -\frac{15}{17}\\\\. I'm skipping the steps here, but let me know if you need to see them.

The result is negative because we're in quadrant 4, when y < 0 so it's when sine is negative.

Therefore,

\sin(2\theta) = 2\sin(\theta)\cos(\theta)\\\\\sin(2\theta) = 2*\left(-\frac{15}{17}\right)*\left(\frac{8}{17}\right)\\\\\sin(2\theta) = -\frac{240}{289}\\\\

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2 years ago
In AQRS OR=7, RS=11 M&lt;=42 IN AUVT VT=26, TU= 44 M
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3 years ago
Jillian measured the distance around a small fish pond as 27 yards. Which would be a good estimate for the distance across the p
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