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3 years ago

Please Please Help thanks

Mathematics

1 answer:

Ilya [14]3 years ago

6 0

That is C 180 times all the numbers

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Which of the following is the simplified version of 3(x + 5) - 6x = 23?

Oxana [17]

Answer:

B.) -3x+15=-23

6 0

3 years ago

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If f(x) = 5x(3exponent) - 2 and g(x) = 2x+1 , find (f+g) (x)

Rus_ich [418]

For this case we must find

$(f + g) (x).$

By definition we have to:

$(f + g) (x) = f (x) + g (x)$

We have the following functions:

$f (x) = 5x ^ 3-2\\g (x) = 2x + 1$

Now, applying the given definition, we have:

$(f + g) (x) = 5x ^ 3-2 + 2x + 1\\(f + g) (x) = 5x ^ 3 + 2x-1$

Answer:

$(f + g) (x) = 5x ^ 3 + 2x-1$

4 0

3 years ago

I want only question number 3

zmey [24]

Answer:

Computers R Us has a better price because it cost less at the same production rate.

Step-by-step explanation: to graph y=23.5x you just plug in numbers. If x = 1, 23.5 (1), which equals y. Now you can keep doing this to get up to 4. You may use a calculator if youd like.

3 0

3 years ago

Jeff is 5 feet tall and casts a shadow 30 inches long. How tall is Marisol if her shadow is 24 inches long?

Westkost [7]

The answer to your problem is that Marisol’s shadow would be 144 feet long

4 0

4 years ago

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What's the next number? 0 , 1/3 , 1/2 , 3/5 , 2/3

madam [21]

Answer:

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 is 5/7

Step-by-step explanation:

The given numbers are;

0, 1/3, 1/2, 3/5, and 2/3

The number sequence is formed adding $\dfrac{1}{\left (\dfrac{n^2 + n}{2} \right ) }$ to each (n - 1)th term to get the nth term number in the sequence, with the first term equal to 0, as follows;

For the 2nd term, the (n - 1)th term is 0, and n = 2, gives;

The

$0 +\dfrac{1}{\left (\dfrac{2^2 + 2}{2} \right ) } = 0 + \dfrac{1}{3} = \dfrac{1}{3}$

For the 3rd term, the (n - 1)th term is 1/3, and n = 3, gives;

$\dfrac{1}{3} +\dfrac{1}{\left (\dfrac{3^2 + 3}{2} \right ) } = \dfrac{1}{3} + \dfrac{1}{6} = \dfrac{1}{2}$

For the 4th term, the (n - 1)th term is 1/2, and n = 4, gives;

$\dfrac{1}{2} +\dfrac{1}{\left (\dfrac{4^2 + 4}{2} \right ) } = \dfrac{1}{2} + \dfrac{1}{10} = \dfrac{3}{5}$

For the 5th term, the (n - 1)th term is 3/5, and n = 5, gives;

$\dfrac{3}{5} +\dfrac{1}{\left (\dfrac{5^2 + 5}{2} \right ) } = \dfrac{3}{5} + \dfrac{1}{15} = \dfrac{2}{3}$

For the next or 6th term, the (n - 1)th term is 2/3, and n = 6, gives;

$\dfrac{2}{3} +\dfrac{1}{\left (\dfrac{6^2 + 6}{2} \right ) } = \dfrac{2}{3} + \dfrac{1}{21} = \dfrac{15}{21} = \dfrac{5}{7}$

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 = 5/7.

6 0

3 years ago