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Andreyy89
3 years ago
13

You need to find the volume of the plastic sphere that holds the gum in your gumball machine. If the diameter is 2 feet, what is

the volume? Use 3.14 to approximate pi. Round your answer to the nearest hundredth.
a 1.33 cubic feet

b 4.19 cubic feet

c 2.36 cubic feet

d 33.49 cubic feet
Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
4 0

For this case we have that by definition, the volume of a sphere is given by:

V = \frac {4} {3} * \pi * r ^ 3

Where:

r: It is the radius of the sphere

According to the statement we have to:

r = \frac {2} {2} = 1 \ft

So the volume is:

V = \frac {4} {3} * \pi * (1) ^ 3\\V = \frac {4} {3} * 3.14\\V = 4.186

Rounding we have that the volume of the sphere is: 4.19 \ ft ^ 3

Answer:

Option B

REY [17]3 years ago
3 0

Answer:

B) 4.19

Step-by-step explanation:

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Pythagorean theorem: a^2 + b^2 = c^2
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4.5^2 + 5.6^2 in the calculator, then find the square root of that. :-)
5 0
3 years ago
Use the graph to the right to write an equation of the line. What is the equation?​
Bingel [31]

Answer:

y = 1/4 x - 2

Step-by-step explanation:

To write the equation of a line, find from the line the slope and y-intercept. The y-intercept is where the line crosses the y-axis which here is at point (0,-2).

The slope of the line is found by writing a ratio between the vertical distance and the horizontal distance between points.

Slope is 1/4.

Substitute m = 1/4 and b = -2 into the slope intercept form y = mx + b.

y = 1/4 x - 2

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3 years ago
Product of squre of x and cube of y
julsineya [31]

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x²y³

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Hope it helps!

Have a nice day:)

6 0
1 year ago
Read 2 more answers
Could you please look at this question?
MrMuchimi

Answer:

  a. see attached

  b. H(t) = 12 -10cos(πt/10)

  c. H(16) ≈ 8.91 m

Step-by-step explanation:

<h3>a.</h3>

The cosine function has its extreme (positive) value when its argument is 0, so we like to use that function for circular motion problems that have an extreme value at t=0. The midline of the function needs to be adjusted upward from 0 to a value that is 2 m more than the 10 m radius. The amplitude of the function will be the 10 m radius. The period of the function is 20 seconds, so the cosine function will be scaled so that one full period is completed at t=20. That is, the argument of the cosine will be 2π(t/20) = πt/10.

The function describing the height will be ...

  H(t) = 12 -10cos(πt/10)

The graph of it is attached.

__

<h3>b. </h3>

See part a.

__

<h3>c.</h3>

The wheel will reach the top of its travel after 1/2 of its period, or t=10. Then 6 seconds later is t=16.

  H(16) = 12 -10cos(π(16/10) = 12 -10cos(1.6π) ≈ 12 -10(0.309017) ≈ 8.90983

The height of the rider 6 seconds after passing the top will be about 8.91 m.

8 0
3 years ago
Reflection Over Parallel Lines Please complete the attached reflection. Thanks!
Allushta [10]

Answer: A(3, -5)

B(6, -2)

C(9, -2)

Step-by-step explanation:

If we have a point (x, y), and we do a reflection over the axis y = a, then the only thing that will change in our point is the value of x.

Now, the distance between x and a must remain constant before and after the reflection.

so if x - a = d

then the new position of the point will be:

(a - d, y) = (2a - x, y).

I will use that relationship for the 3 points

A)

We start with the point (1, -5)

The reflection over y = -1 leaves.

The distance between 1 and -1 is = 1 - (-1) = 2.

Then the new point is (-1 - 2, -5) = (-3, -5)

Now we do a reflection over y = 1, so D = -3 - 1 = -2

Then the new point is:

A = (1 -(-2), -5) = (3, -5)

B) (2, -2)

Reflection over y = -1.

distance, d = 2 - (-1) = 3

the point is (-1 - 3, -2) = (-4, -2)

Now, a reflection over y = 1.

The distance is D = -4 - 1 = -5

The new point is (1 - (-5), 2) = (6, -2)

C) (5, -2)

reflection over y = -1

Distance: D = 5 - ( - 1) = 6

New point: (-1 - 6, -2) = (-7, -2)

Reflection over y = 1.

Distance D = -7 - 1 = -8

New point ( 1 - (-8), -2) = (9, -2)

4 0
3 years ago
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