Here's link to the answer:
linkcutter.ga/gyko
Answer:
d. 20+10+5+2.5+...
Step-by-step explanation:
No geometric series with a common ratio of magnitude greater than 1 will have a finite sum. Nor will any arithmetic series.
Those descriptions exclude answer choices a, b, c. Choice d is a geometric series with a common ratio of 1/2, so will have a finite sum. (It is 40.)
Answer:
There are 12 pentapods and 8 Tripods, which in total add up to 84 feet.
Step-by-step explanation:
Given that both the Tripods and the Pentapods have, at least, 3 feet (the Pentapods have 5), and that in total between both groups they add 20 heads and 84 feet, the following logical reasoning can be made:
If there are 20 heads, there are 20 Martians in all. Each of them has, at least, 3 feet, with which in principle the 20 Martians would add up to a total of 60 feet (20 x 3). Therefore, there is a surplus of 24 feet (84 - 60).
If the Pentapods have 2 feet more than the Tripods, the number of Pentapods in the total Martians is determined by that difference. Thus, if there are 24 feet left, there are 12 Pentapods (24/2).
Therefore, in the group of Martians there are 12 pentapods (12 x 5 = 60) and 8 Tripods (8 x 3 = 24), which in total add up to 84 feet (60 + 24).
Answer:
d = √5 ≈ 2.24
Step-by-step explanation:
B is located at (1, 3) and B' is located at (3, 4)
Distance formula:
[tex] d = \sqrt{(xB' - xB)^2 + (yB' - yB)^2}[\tex]
replacing with the coordinates of the points:
[tex] d = \sqrt{(3 - 1)^2 + (4 - 3)^2}[\tex]
[tex] d = \sqrt{4 + 1}[\tex]
d = √5 ≈ 2.24
A is the answer to this question no doubt
