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sukhopar [10]
3 years ago
7

The length of a rectangular garden is 3 yards more than its width. The area of the garden is 40 square yards. Find the length of

the garden.

Mathematics
1 answer:
Goryan [66]3 years ago
4 0

Answer:

length=8 , wide=5

Step-by-step explanation:

Let length=x and wide=y

convert the question into two equations

3+y=x .......1

xy=40 .......2

so we need to substitute x into y or y into x

x=3+y ,

(3+y)y=40

y²+3y=40

y²+3y-40=0

from that use calculator or manually factorise it

(y+8)(y-5)=0

y= –8 , y=5

we need to choose positive answer so y=5

then find for x

5x=40

x=8

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Select all the statements that describe the expression 5+2x.
sergejj [24]

Answer:

B, E

Step-by-step explanation:

Answer A is wrong: 5 + 2 + x

Answer C is wrong: 5 + x + x

Answer D is wrong: 5 + x*x

F is wrong, because a product is the result of multiplying.

6 0
3 years ago
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Originally 21 acts were tentatively to perform at the arena ; only 10 have been booked. What is the shortfall if the other acts
Yakvenalex [24]
Find the number of acts not booked = 21 - 10 = 11

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The answer and how to do it
inessss [21]
Alright, here is how to do it:
First you are going to want to multiply 4x4. [That is Dino's Charges for 4 Sandwiches.] So once you've done that, you should get 16

Now, you're going to want to multiply 8x4. [That is Carla's charges for 4 Sandwiches.] So once you've done that, you should get 24.

Now, to find the difference you will have to subtract them. 24-16 = 18.
Now that we've done this we now know your answer is:
Carla's sandwiches cost more than Dino's sandwiches. The difference is 18 dollars.
-------------------------
I hope I helped, if I did; please give me brainliest. :)
4 0
3 years ago
In the equation 8x - 1=3x+4 the variable x represents the same value. Which value of x is the solution of the equation x = 0 1 2
OleMash [197]

the AnSwEr is

12 because 8x - 1=3x+4 the variable x represents the same value and x= 0

7 0
3 years ago
Cual es la derivada de ()=√x sin
fgiga [73]

Answer:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

Step-by-step explanation:

We assume that the function of interest is:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

3 0
3 years ago
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