42. th gmtv rg eg eg gen h
Answer:
Option a.

Step-by-step explanation:
You have the following limit:

The method of direct substitution consists of substituting the value of
in the function and simplifying the expression obtained.
We then use this method to solve the limit by doing 
Therefore:


By definition, any number raised to exponent 0 is equal to 1
So


Finally

-- Find how much 'y' changes from the first point to the second one.
-- Find how much 'x' changes from the first point to the second one.
-- The slope of the line going from the first point to the second one is
(change in 'y') / (change in 'x') .
I=PRT/100
1. Make R (rate) subject
R/100= I/PT
2. Substitute and calculate
r/100= i/pt
r/100= 40/400 × 1
(<em>4</em><em>0</em><em> </em><em>i</em><em>s</em><em> </em>from 440-400.<em>T</em><em>h</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>e</em><em>r</em><em>e</em><em>s</em><em>t</em>)
r/100= 0.1
r/100×100= 0.1×100
r=10% (interest rate per year)
To confirm
I=PRT
I= 400×10/100×1
I= $40 (Interest)
Answer:
The radius is: 
Step-by-step explanation:
The equation of a circle in center-radius form is:

Where the center is at the point (h, k) and the radius is "r".
So, given the equation of the circle:

You can identify that:

Then, solving for "r", you get that the radius of this circle is:
