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Mnenie [13.5K]
3 years ago
7

How many digits you need to write all 2-digit numbers?

Mathematics
1 answer:
Julli [10]3 years ago
4 0

Answer:

The total answer is 90.

I hope you have a great day :)

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I need to simplify this
Anon25 [30]
Your answer would be
-7-(-i)+6-3i
3 0
3 years ago
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A recent study of 26 city residents showed that the time they had lived at their present address has a mean of 10.3 years with t
svetlana [45]

Answer:

The 95% confidence interval is  9.15<  \mu < 11.45

Step-by-step explanation:

From the question we are told that

     The sample size is  n =  26

      The mean is  \= x =  10.3

       The standard deviation is  s =  3

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>   E =  1.96 *  \frac{3}{\sqrt{26} }

=>   E = 1.1532

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>   10.3  -1.1532 <  \mu < 10.3  +  1.1532

=>    9.15<  \mu < 11.45

7 0
3 years ago
179 divided by 10 over the power of 2​
Evgen [1.6K]

Answer:

I got 1.79

Step-by-step explanation:

If you're saying 179 divided by 10 to the second power it would be 1.79.

6 0
2 years ago
What did Cinderella say to the photograph
borishaifa [10]
Is this a joke ? If so some day my prints will come dad
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Please help me with this
Papessa [141]

Answer:

  see attached

Step-by-step explanation:

The grid show the non-possibilities in red, with each number corresponding to the statement that eliminates that choice. The green square (with black text) shows the one combination that is specified already (by statement 4). The lighter green numbers show possible alternatives: first period may be Schiller or English, and room 113 will be the other one. Similarly, Art may be 3rd period or Thomlinson.

__

These choices (light green 5, light green 6) give rise to four possibilities. Working through them, you run into inconsistencies if you choose Schiller for first period. (Art must be, but can't be, in room 112.) That leaves two possibilities.

Again, you run into inconsistencies if you choose Thomlinson as the Art teacher. (The class in 112 is 2 periods after Xavier's class, not 1.)

Hence, the only viable pair of remaining choices is Schiller in room 113 and art in 3rd period.

The final schedule is shown in the attachment.

_____

<em>Additional comment</em>

When I'm working these on paper, I use an X to mark any impossible combinations, and a circle (O) to mark a known combination. In any given 4×4 square of the grid, the remaining cells of the row and column containing a O must be Xs. Consistency must be maintained between rows and columns. This often means filling a circle in one place may result in a circle being filled in another place. Of course, once 3 of the squares in a row or column have Xs, the remaining one must be O.

6 0
2 years ago
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