A 10-foot ladder must make an angle of 30° with the ground if it is to reach a certain window. What angle must a 20-foot ladder
make with the ground to reach the same window?
2 answers:
Answer:
15°
Explanation:
Let the height of the window be 'h'
Let the angle the second ladder make with the ground be 'Ф'
From the image uploaded, height of the window 'h' will be calculated from figure a
Using SohCahToa; we calculate the height of the window 'h' that 10-foot ladder must reach.
sine30 = opposite/hypotenuse
sine 30 = h/10ft
h = 10ft × sine30
h = 10ft × 0.5
h= 5ft; height of the window is 5 foot
using figure b and substituting the value of h as 5ft, will calculate 'Ф' for 20-foot ladder
sine Ф = 5ft/20ft
sine Ф = 1/4
sine Ф = 0.25
Ф = arc sine (0.25)
Ф = 14.4775°
Ф ≅ 15°
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Answer:
<em>The programming language is not stated; however, I'll answer using Python programming language (</em><em>Se</em><em>e attachment</em><em> </em><em>for</em><em> </em><em>proper </em><em>for</em><em>mat</em><em>)</em>
tuition = 10000
rate = 0.04
for i in range(1,15):
tuition = tuition + tuition * rate
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
Explanation:
<em>The first 2 lines initializes tuition and rate to 10000 and 0.04 respectively</em>
tuition = 10000
rate = 0.04
<em>The next line iterates from year 1 to year 14</em>
for i in range(1,15):
<em>This line calculates the tuition for each year</em>
tuition = tuition + tuition * rate
<em>The next 3 lines prints the tuition for year 1 to year 10</em>
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
<em>The next 3 lines prints the tuition at the 4th year after year 10 (i.e. year 14)</em>
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
