Ur answer is 100.44000000000001
Answer:
Volume
Figure 1 = 56 cube units
figure 2 = 60 cube units
figure 3 =72 cube units
Surface area
Figure 1 = 100 square units
figure 2 = 104 square units
figure 3 =108 square units
Step-by-step explanation:
From the all figure we can see that each figure made up of unit cubes
<u>Figure 1</u>
<u>Surface area </u>
Large cuboid portion =2 x (6 x 2 ) + (6 x 4) + 2 x(4 x 2) + 16
= 24 + 24 + 16 + 16 = 80 unit square
Small cuboid portion = (4 x 2) + (2 x 2) + (4 x 2) = 8 + 4 + 8 = 20
Total surface area = 80 + 20 = 100 unit square
<u>Volume</u>
Small cuboid = 4 x 2 = 8
Large cuboid = 6 x 4 x 2 = 48 cube unit
Total volume = 48 + 8 = 56 cubs units
<u>Figure 2</u>
<u>Surface area </u>
Total surface area =24 + 18 + 36 + 20 + 6 = 104 unit square
<u>Volume</u>
Small cuboid = 6 x 2 = 12
Large cuboid = 6 x 4 x 2 = 48 unit square
Total volume = 48 + 12 = 60 cube units
<u>Figure 3</u>
<u>Surface area </u>
Total surface area = 48 + 36 + 24 = 108 square units
<u>Volume</u>
Total volume = 6 x 4 x 3 = 72 cube units
Answer:
b im positive it B but if im wrong message me
Yes it is because 18÷6 is 3 and 6×3=18
Given:
The figure of a triangle LMN.
P is the centroid of triangle LMN.
To find:
14. Find the value of PN if QN=30.
15. Find the value of PN if QN=9.
Solution:
We know that the centroid in the intersection of medians of a triangle and centroid divides each median in 2:1.
Since P is the centroid it means NQ is the median from vertex N. It means P divides the median NQ in 2:1. So, PN:PQ=2:1.
14. We have QN=30.
Therefore, the value of PN is 20 when QN=30.
15. We have QN=9.
Therefore, the value of PN is 6 when QN=9.
