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Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

8 0

B is the answer to that

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EVALUATE THE FOLLOWING -15 x 6

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the answer is 90

Step-by-step explanation:

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3 years ago

A lawn sprinkler sprays water 7 feet in every direction as it rotates. What is the distance around the outside circle of water?

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The answer is B. To find the Circumference (what you're looking for) you use 2×pi×radius. Which is 2×pi×7. In terms of pi that's just 2×7, which equals 14. So that means your answer is 14pi.

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What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE

Nutka1998 [239]

Answer:

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),$ $\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

Step-by-step explanation:

Let points D, E and F have coordinates $(x_D,y_D),\ (x_E,y_E)$ and $(x_F,y_F).$

1. Midpoint M of segment DF has coordinates

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).$

2. Midpoint N of segment EF has coordinates

$\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

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3 years ago

Find the square root by factor <br>21904

mihalych1998 [28]

$21904|2\\10952|2\\.\ 5476|2\\.\ 2738|2\\.\ 1369|37\\.\ \ \ \ 37|37\\.\ \ \ \ \ \ 1|\\\\21904=2\times2\times2\times2\times37\times37=2^4\times37^2\\\\\sqrt{21904}=\sqrt{2^4\times37^2}=\sqrt{2^4}\times\sqrt{37^2}=2^2\times37=4\times37=148$

$\sqrt{21904}=\sqrt{4\times5476}=2\sqrt{4\times1369}=2\times2\sqrt37\times37}=4\times37=148$