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2 years ago

Please help me with complement or supplement of an angles.

Mathematics

1 answer:

rosijanka [135]2 years ago

6 0

Answer:

Step-by-step explanation:

If we look at the picture, we can see that its a right angle having a 90 degree.

We can make a equation with this as we know that m1 and m2 has to equal 90

x + y = 90

Since we know that m2 = 30 we can plug 30 for x

(30) + y = 90

Now we simply moving the 30 to the 90

y = 90 - 30

y = 60

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Peter threw the football 72 feet. How many yards did he throw the football ?

Darya [45]

1 yard = 3 feet.

Divide total feet by 3 to get yards:

72 feet / 3 = 24 yards.

3 0

3 years ago

MATH

castortr0y [4]

Answer:

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Step-by-step explanation:

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2 years ago

I will make u a brainliest plz help me

satela [25.4K]

Answer: B) Infinitely many solutions; both equations are equivalent

==============================================================

Work Shown:

x+y = 4 ... start with the first equation

x + (-x+4) = 4 ... replace y with (-x+4)

x-x+4 = 4

0x+4 = 4

0+4 = 4

4 = 4 ... this is a true statement regardless of what x you pick

So there are infinitely many solutions. Each solution (x,y) is of the form (x,-x+4). All solutions fall on the line y = -x+4 which is equivalent to x+y = 4. Note how we add x to both sides.

Or you could start with x+y = 4 and subtract x from both sides to get y = -x+4. Either way, we're dealing with the same equation which is why they both graph out the same line.

6 0

3 years ago

Read 2 more answers

Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.

Olenka [21]

Answer:

$\frac{(9-x)}{3x}$

Step-by-step explanation:

we have

$\frac{\frac{2}{x-3}-\frac{3}{x}}{\frac{3}{x-3}}$

step 1

Solve the numerator of the quotient

$\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}$

step 2

substitute in the original expression

$\frac{\frac{9-x}{(x-3)x}}{\frac{3}{x-3}}$

$\frac{(x-3)(9-x)}{3x(x-3)}$

step 3

simplify

$\frac{(9-x)}{3x}$

5 0

3 years ago

A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat

Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

Step-by-step explanation:

1) Data given and notation

$s^2 =16$ represent the sample variance

s=4 represent the sample standard deviation

$\bar x$ represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical values.