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2 years ago

Please help me with complement or supplement of an angles.

Mathematics

1 answer:

rosijanka [135]2 years ago

6 0

Answer:

Step-by-step explanation:

If we look at the picture, we can see that its a right angle having a 90 degree.

We can make a equation with this as we know that m1 and m2 has to equal 90

x + y = 90

Since we know that m2 = 30 we can plug 30 for x

(30) + y = 90

Now we simply moving the 30 to the 90

y = 90 - 30

y = 60

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The largest prime factor of thirty-five is _____. 7 5 9 11

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Since 9 and 11 do not factor 35, they are not the answer.

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The x3 was supposed to be an exponent not 3x

mote1985 [20]

Answer:

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Step-by-step explanation:

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3 years ago

50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle

aalyn [17]

Answer:

$EF=4\sqrt{3}$

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

$A_{\text{rect}}=8(6)=48\text{ cm}^2$

The area of the triangle is 1/4 of this. Therefore:

$\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2$

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

$\displaystyle 12=\frac{1}{2}(DE)(DF)$

Since DE = DF:

$24=DF^2$

Thus:

$DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE$

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

$(DE)^2+(DF)^2=(EF)^2$

Therefore:

$(2\sqrt6)^2+(2\sqrt6)^2=EF^2$

Square:

$24+24=EF^2$

Add:

$EF^2=48$

And finally, we can take the square root of both sides:

$EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}$

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