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aniked [119]
2 years ago
11

Please help me with complement or supplement of an angles.

Mathematics
1 answer:
rosijanka [135]2 years ago
6 0

Answer:

60

Step-by-step explanation:

If we look at the picture, we can see that its a right angle having a 90 degree.

We can make a equation with this as we know that m1 and m2 has to equal 90

x + y = 90

Since we know that m2 = 30 we can plug 30 for x

(30) + y = 90

Now we simply moving the 30 to the 90

y = 90 - 30

y = 60

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59-(2c+3)=4(c+7)+c.
alisha [4.7K]

Step-by-step explanation:

{:}\leadsto\sf 59-(2c+3)=4 (c+7)+c

{:}\leadsto\sf 59-2c-3=4c+28+c

{:}\leadsto\sf 56-2c=5c+28

{:}\leadsto\sf 5c+28=56-2c

{:}\leadsto\sf 5c+2c=56-28

{:}\leadsto\sf 7c=28

{:}\leadsto\sf c={\dfrac {28}{7}}

{:}\leadsto\sf c=4

4 0
2 years ago
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Evaluate the expression using the values in the left column to complete the table
egoroff_w [7]

Answer/Step-by-step explanation:

A. 4b + 3b

Using b = 2

4(2) + 3(2) = 8 + 6 = 14

Using b = 4

4(4) + 3(4) = 16 + 12 = 28

Using b = 6

4(6) + 3(6) = 24 + 18 = 42

Using b = 8

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Using b = 10

4(10) + 3(10) = 40 + 30 = 70

Using b = 2

4(12) + 3(12) = 48 + 36 = 84

B. 3(x - 2)

Using x = 3

3(3 - 2) = 3(1) = 3

Using x = 5

3(5 - 2) = 3(3) = 9

Using x = 7

3(7 - 2) = 3(5) = 15

Using x = 9

3(9 - 2) = 3(7) = 21

Using x = 11

3(11 - 2) = 3(9) = 27

Using x = 13

3(13 - 2) = 3(11) = 33

C. 5(4a - 1)

Using a = 2

5(4(2) - 1) = 5(8 - 1) = 5(7) = 35

Using a = 3

5(4(3) - 1) = 5(12 - 1) = 5(11) = 55

Using a = 4

5(4(4) - 1) = 5(16 - 1) = 5(15) = 75

Using a = 5

5(4(5) - 1) = 5(20 - 1) = 5(19) = 95

Using a = 6

5(4(6) - 1) = 5(24 - 1) = 5(23) = 115

Using a = 7

5(4(7) - 1) = 5(28 - 1) = 5(27) = 135

D. 6y - 2y + 4

Using y = 2

6(2) - 2(2) + 4 = 12 - 4 + 4 = 12

Using y = 3

6(3) - 2(3) + 4 = 18 - 6 + 4 = 18 - 2 = 16

Using y = 5

6(5) - 2(5) + 4 = 30 - 10 + 4 = 30 - 6 = 24

Using y = 10

6(10) - 2(10) + 4 = 60 - 20 + 4 = 60 - 16 = 44

Using y = 8

6(8) - 2(8) + 4 = 48 - 16 + 4 = 48 - 12 = 36

Using y = 6

6(6) - 2(6) + 4 = 36 - 12 + 4 = 36 - 8 = 28

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3 years ago
What is the answer to this too?
Radda [10]
The answer to this is 5%
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2 years ago
How to prove two equations have infinite solutions?
laiz [17]
To prove two equations have infinite solutions, you have to prove that those two equations are the same equations, but in a different form.

For example: Prove the equations are infinite
5y=2x+7
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