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GrogVix [38]
3 years ago
6

Donna had $9 in her bank account. She made $16 when she mowed her neighbors' lawns. Then,

Mathematics
2 answers:
Trava [24]3 years ago
4 0

Answer:

$-2

Step-by-step explanation:

GaryK [48]3 years ago
4 0

Answer:

$-2

Step-by-step explanation:

9+16 = 25 - 27 = $-2

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Ann and Betty shared some money in the ratio 2:3. Ann received 120 dollars.
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there is an unknown number in the sequence counting backward. The number is after 48. The number is before 46. What is the unkno
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The unknown number is 47.
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What is 2a + 3x + a + 5x =
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There are many ways to measure the reading ability of children. Research designed to improve reading performance is dependent on
ELEN [110]

Answer:

A 90% confidence interval to estimate the mean DRP score in Henrico County Schools  is =32±2.7280

i.e. C.I.  [29.3,34.7]

Hence the results are not significant.

Step-by-step explanation:

Given:

Total no of students =44

True mean =32

Standard deviation=11

And all 4 students score also given.

To Find:

90 % confidence interval and conclusion on it.

Solution:

Here for C.I. we required mean, standard deviation and no of students.

So mean =32,S.D.=11 and n=44

Therefore , For 90 % interval Zscore is Z=1.645

C.I.=mean±Z[Standard  deviation/Sqrt(n)]

=32±1.645[11/Sqrt(44)]

=32±1.645[1.6583]

=32±2.7280

i.e. C.I.  [29.3,34.7]

Now Here to commit on calculated interval we should check  value of Z-score

So we need to calculate the sample mean.

Sample mean =Sum of all values /Total no of values.

=[40+ 26 +39+ 14+ 42+ 18 +25+ 43+ 46 +27 +19+ 47+ 19 +26+ 35 +34+ 15+ 44 40+ 38+ 31+ 46 +52 +25+ 35 +35+ 33 +29 +34 +41 +49+ 28+ 42+ 47 +35 +48 +22 33+ 41 +51 +27 +14+ 54 +45]/44

=34.86

Z-score=(sample mean -true mean)/[standard deviation/Sqrt(n)]

=(34.86-32)/[11/Sqrt(44)]

Z=1.72465

For ,

P(Z≥1.72465)=0.08544

For 0.05 significance level  the results are not significant at  p<0.01.

Researcher claimed mean is not correct upto 0.05 significant level

i.e calculated mean and Sample mean are different.

Hence the results are not significant.

6 0
3 years ago
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