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snow_tiger [21]
3 years ago
13

Calculate the volume of the pyramid above. V = ? m3

Mathematics
1 answer:
Vadim26 [7]3 years ago
3 0
V = lwh/3
= 5x3x1/3
= 15/3
= 5
Therefore the volume is 5 meter cubed.
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Given the data set (18,14, 12, 14, 11, 11, 19, 20, 16, 11), which statements are correct?
Anuta_ua [19.1K]

The correct statement is that the <u>range of the data is 9</u>

<h3>Range of a data</h3>

The formula for calculating the range of data is expressed as:

Range = Highest value - Lowest value

From the given data

  • Highest value = 20
  • Lowest value = 11

Substituting into the formula

Range = 20 - 11

Range = 9

Hence the correct statement is that the <u>range of the data is 9</u>

Learn more on range here: brainly.com/question/2264373

6 0
2 years ago
nia has number cards for the 2,3,8,9,5 what are all the different ways one can arrange the cards of even number of two in the te
Sonbull [250]
There are 6 different ways:

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3 years ago
Divide 3xsquared - 11x - 4 by x - 4<br><br>a. x+1<br>b. x-23<br>c. 3x+1<br>d. 3x-23​
Dmitriy789 [7]

Answer:

c. 3x+1

Step-by-step explanation:

Since the divisor is in the form of x - c, use what is called Synthetic Division. Remember, in this formula, <em>-c</em> gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 3 −11 −4

↓ 12 4

_______________

3 1 0 → 3x + 1

You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [3x² - 11x - 4]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 3 in your quotient can be a 3x, and the 1 follows right behind it, giving you the quotient of 3x + 1.

I am joyous to assist you anytime.

5 0
3 years ago
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second. Use the central limi
Mila [183]

Answer:

0.048 is the probability that more than 950 message arrive in one minute.

Step-by-step explanation:

We are given the following information in the question:

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.

Let X be the number of messages arriving at a multiplexer.

Mean = 15

For poison distribution,

Mean = Variance = 15

\text{Standard Deviation} = \sqrt{\text{Variance}} = \sqrt{15} = 3.872

From central limit theorem, we have:

z = \displaystyle\frac{x-n\mu}{\sigma\sqrt{n}}

where n is the sample size.

Here, n = 1 minute = 60 seconds

P(x > 950)

P( x > 950) = P( z > \displaystyle\frac{950 - (60)(15)}{\sqrt{(15)(60)}}) = P(z > 1.667)

= 1 - P(z \leq 1.667)

Calculation the value from standard normal z table, we have,  

P(x > 950) = 1 - 0.952 = 0.048

0.048 is the probability that more than 950 message arrive in one minute.

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3 years ago
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