Given the data set (18,14, 12, 14, 11, 11, 19, 20, 16, 11), which statements are correct?
Anuta_ua [19.1K]
The correct statement is that the <u>range of the data is 9</u>
<h3>Range of a data</h3>
The formula for calculating the range of data is expressed as:
Range = Highest value - Lowest value
From the given data
- Highest value = 20
- Lowest value = 11
Substituting into the formula
Range = 20 - 11
Range = 9
Hence the correct statement is that the <u>range of the data is 9</u>
Learn more on range here: brainly.com/question/2264373
There are 6 different ways:
23,598
23,958
25,398
25,938
29,538
29,358
Answer:
c. 
Step-by-step explanation:
Since the divisor is in the form of
, use what is called Synthetic Division. Remember, in this formula, <em>-c</em> gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
4| 3 −11 −4
↓ 12 4
_______________
3 1 0 → 3x + 1
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [3x² - 11x - 4]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 3 in your quotient can be a 3x, and the 1 follows right behind it, giving you the quotient of
.
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Answer:
0.048 is the probability that more than 950 message arrive in one minute.
Step-by-step explanation:
We are given the following information in the question:
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.
Let X be the number of messages arriving at a multiplexer.
Mean = 15
For poison distribution,
Mean = Variance = 15

From central limit theorem, we have:
where n is the sample size.
Here, n = 1 minute = 60 seconds
P(x > 950)
Calculation the value from standard normal z table, we have,

0.048 is the probability that more than 950 message arrive in one minute.
Less than $3 because 25/7/2