Answer:
- Tamara needs to cover a total of <u>476</u> square feet.
- Tamara <u>will</u> have enough material to cover all four walls.
Step-by-step explanation:
If the room dimensions are 8 1/3 feet by 11 1/2 feet, the perimeter length is ...
P = 2(L+W) = 2(8 1/3 +11 1/2) = 2(19 5/6) = 39 2/3 feet
The area of the walls is the product of this perimeter length and the height of the wall. If that height is 12 feet, then the wall area is ...
A = PH = (39 2/3 ft)(12 ft) = 476 ft²
Tamara needs to cover a total of <u>476</u> square feet.
__
If Tamara orders 480 square feet of material, ...
Tamara <u>will</u> have enough to cover all four walls.
Step-by-step explanation:
By using Implicit Differentiation,
d/dx (y² + xy - x²) = d/dx (11x)
d/dx (y²) + d/dx (xy) - d/dx (x²) = 11
2y * dy/dx + x * dy/dx + y - 2x = 11
dy/dx (2y + x) = 11 + 2x - y
dy/dx = (11 + 2x - y) / (2y + x).
At the point (2, 3), we have x = 2, y = 3.
=> dy/dx = (11 + 2(2) - (3)) / (2(3) + (2))
= 12 / 8 = 1.5.
P.S. Your question is weird because (2,3) is not on the graph, let me know what is the correct question thanks!
Original price of the swimsuit = x
If something was discounted 65%, that means you are paying 35% for it.
(100% - 65% = 35% or 0.35)
x(0.35) = 20.30
divide both sides by 0.35
x = 58
The swimsuit was originally 58 dollars.
Answer:
The amount invested in CDs is $1,340
The amount invested in the stock portafolio is $6,900
The amount invested in the saving accounts is $2,300
Step-by-step explanation:
Let
x ---->the amount invested in CDs at 2.1%
y ---> the amount invested in the stock portfolio at 2.5%
z ---> the amount invested in the savings account at 1.5%
----> equation A
----> equation B
substitute equation B in equation A


----> equation C
we know that
The total interest earned by the three amount must be equal to $231.69
so
----> equation D
substitute equation B and equation C in equation D

solve for y




<em>Find the value of x</em>


<em>Find the value of z</em>


Well round to the nearest cent means to the nearest .01
So if the number is ex .0328
You round to .03
And if the number is ex .06831
You round to .07
Meaning if the number after .01 or .0_ is greater than 5 than you round up and if it's 4 or lower than you keep the number there
Sorry can't do much if this is an actual problem because you only said round to the nearest cent.