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lisov135 [29]
3 years ago
10

What is the equation of the line that contains the point (-5, -1) and has a slope of 4? Write in slope-intercept form.

Mathematics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

B.y = 4x+19

Step-by-step explanation:

We are given a point and a slope, we can write the equation in point slope form

y-y1 = m (x-x1)

y--1 = 4(x--5)

y+1 = 4(x+5)

We want the equation in slope intercept form(y=mx+b)

Distribute

y+1 =4x+20

Subtract 1 from each side

y+1-1 = 4x+20-1

y = 4x+19

Zarrin [17]3 years ago
3 0

\huge{\boxed{\text{B.}\ y=4x+19}}

Point-slope form is y-y_1=m(x-x_1), where m is the slope and (x_1, y_1) is a point on the line.

Substitute the values. y-(-1)=4(x-(-5))

Simplify the negative subtraction. y+1=4(x+5)

Distribute the 4. y+1=4x+20

Subtract 1 on both sides. \boxed{y=4x+19}

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