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soldi70 [24.7K]
2 years ago
11

1. What is the slope of the line tangent to the curve defined by y2 + xy - x2 = 11x at the point (2, 3)?

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
7 0

Step-by-step explanation:

By using Implicit Differentiation,

d/dx (y² + xy - x²) = d/dx (11x)

d/dx (y²) + d/dx (xy) - d/dx (x²) = 11

2y * dy/dx + x * dy/dx + y - 2x = 11

dy/dx (2y + x) = 11 + 2x - y

dy/dx = (11 + 2x - y) / (2y + x).

At the point (2, 3), we have x = 2, y = 3.

=> dy/dx = (11 + 2(2) - (3)) / (2(3) + (2))

= 12 / 8 = 1.5.

P.S. Your question is weird because (2,3) is not on the graph, let me know what is the correct question thanks!

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Step-by-step explanation:

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Can you guys help?<br> Need to find x, BA, DA
7nadin3 [17]

Answer:

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4 0
3 years ago
PLEASE ANSWER ASAP
Hoochie [10]

First, let's ignore the answer choices and solve for a value of x ourselves.

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The value of x is going to be greater than 6, and so, we can observe the answer choices, and whichever value is greater than 6, is the correct answer.

<h3>In this case, there is only one answer, and that is D, x = 10.</h3>
3 0
3 years ago
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7 0
3 years ago
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