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vekshin1
3 years ago
10

Find the vertex of the parabola y= x^2-2x-1 vertex (?,?)

Mathematics
2 answers:
nignag [31]3 years ago
7 0
y=a(x-h)^2+k \Rightarrow \hbox{vertex}=(h,k)\\\\
y=x^2-2x-1\\
y=x^2-2x+1-2\\
y=(x-1)^2-2 \Rightarrow \hbox{vertex}=(1,-2)
SpyIntel [72]3 years ago
5 0
y=ax^2+bx+c\\\\vertex:(x_v;\ y_v)\\\\x_v=\frac{-b}{2a}\ and\ y_v=f(x_v)


y=x^2-2x-1\\\\a=1;\ b=-2;\ c=-1\\\\x_v=\frac{-(-2)}{2\cdot1}=\frac{2}{2}=1\\\\y_v=1^2-2\cdot1-1=1-2-1=-2\\\\Answer:(1;-2)
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