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Novosadov [1.4K]

3 years ago

12

What is -1 OVER 7 Multiplyed by 1 over 5

1 answer:

ycow [4]3 years ago

5 0

-1/35 because you multiply the 2 denominators and numerators together. -1 times 1 is -1, 7 times 5 is 35. Make that as a fraction to get -1/35.

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How do i solve this question?

Andrews [41]

when it comes to checking if a function is even or odd, it boils down to changing the argument, namely x = -x, and if the <u>resulting function is the same as the original</u>, then is even, if the <u>resulting function is the same as the original but negative</u>, is odd, if neither, well then neither :).

anyway, that said, let's first expand it and then plug in -x,

$\bf f(x)=(x^2-8)^2\implies f(x)=(x^2-8)(x^2-8)\implies f(x)=\stackrel{FOIL}{x^4-16x^2+64}\\\\[-0.35em]~\dotfill\\\\f(-x)=(-x)^4-16(-x)^2+64\qquad \begin{cases}(-x)(-x)(-x)(-x)=x^4\\(-x)(-x)=x^2\end{cases}\\\\\\f(-x)=x^4-16x^2+64\impliedby \stackrel{\textit{same as the original}}{Even}$

3 0

4 years ago

Help need explanation

Liula [17]

If you multiply all 3 numbers (x*y*z) you will get the answer

4 0

3 years ago

Read 2 more answers

Solve the system of equations given below.

eduard

Answer:

The system of this equation is ( -1, 10) which is Option A.

Step-by-step explanation:

Solve for y in the first equation.

$y = - 5x + 5 \\ - 2y = - x - 21$

Replace all occurrences of yy with -5x+5 in each equation.

$10x - 10 = - x - 21 \\ y = - 5x + 5$

Solve for x in the first equation.

$x = - 1 \\ y = - 5x + 5$

Replace all occurrences of x with -1 in each equation.

$y = 10 \\ x = - 1$

The solution to the system is the complete set of ordered pairs that are valid solutions.

(−1, 10)

<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>system</u><u> </u><u>of</u><u> </u><u>this</u><u> </u><u>equation</u><u> </u><u>is</u><u> </u><u>(</u><u>-1</u><u>,</u><u> </u><u>10</u><u>)</u><u>.</u><u> </u>

<u>Option</u><u> </u><u>A</u><u>.</u>

5 0

3 years ago

Find the square Root of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B37%7D%20" id="TexFormula1" title=" \sqrt{37} " alt="

Zolol [24]

Answer:

$\approx \frac{73}{12}\left(1 - \frac{1} {2\cdot73^2}\right)$

Step-by-step explanation:

$= \sqrt{\frac{73^2-1) 1}{12^2}} \\$

$= \sqrt{\frac{73^2}{12^2}\cdot\frac{73^2-1}{73^2}} \\$

$= \sqrt{\frac{73^2}{12^2}}\sqrt{\frac{73^2-1}{73^2}}\\$

= $\frac{73}{12}\sqrt{1 - \frac{1}{73^2}} \\$

$\approx \frac{73}{12}\left(1 - \frac{1} {2\cdot73^2}\right)$

8 0

3 years ago

Help me. ill give brainliest :D

Setler79 [48]

Answer:

whoa

Step-by-step explanation:

4 0

3 years ago