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lisabon 2012 [21]
3 years ago
12

Traits that organisms acquire, or learn, during their lifetime will be passed on to their offspring. True False

Chemistry
1 answer:
Viktor [21]3 years ago
4 0
False. Because something you acquire is not something you inherent. hope this helps


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Is nuts and bolts an example of a element or a compound?
goldfiish [28.3K]

Answer:

In this activity, we will pretend that nuts, washers and bolts are 3 kinds of elements. A single washer represents an atom of WASHER. A single nut represents an atom of NUT and a single bolt represents an atom of BOLT. Atoms can be put together to form compounds.

4 0
3 years ago
Read 2 more answers
Write the balanced equation for each of the following changes and identify whether heat is a product or needed to start the reac
storchak [24]

Explanation:

(a) the sublimation of dry ice [conversion of CO2(s) directly to CO2(g)]

The balanced equation is given as;

CO2(s) --> CO2(g)

This reaction is endothermic, hence; Heat is a reactant and is needed to start the reaction.

(b) the reaction of 1 mol of sulfur dioxide with oxygen.

The balanced equation is given as;

2SO2 + O2 --> 2SO3

This reaction is exothermic, hence; Heat is a product and is given off by the reaction.

5 0
4 years ago
Which of the following are lost or gained during a nuclear reaction?
hram777 [196]

Answer:

I think that is electrons and nucleus

Explanation:

It makes sense

5 0
3 years ago
Read 2 more answers
A compound is 85.7% C and 14.3% H and has a molar mass of 98g/mol, what is the compounds molecular formula?
vaieri [72.5K]

Answer:

Molecular Formula => (CH₂)₇ => C₇H₁₄      

Explanation:

Empirical ratio is calculated from the sequence...

%/100wt => grams/100wt => moles => mole ratio => reduce mole ratio => Empirical Ratio

C: 85.7% => 85.7g => (85.7/12)mol = 7.14 mole

H: 14.3%  => 14.3g =>     (14.3/1)mol = 14.3 mole

C:H mole ratio => 7.14:14.3

Reduced mole ratio (divide by the smaller mole value) => (7.14/7.14):(14.3/7.14) => Empirical Ratio => 1:2 => Empirical Formula => CH₂

Molecular Wt = Whole No. Multiple of Empirical Formula Wt.

M.Wt = N(Emp Wt) => 98g = N(14g) => N = 7

∴Molecular Formula => (CH₂)₇ => C₇H₁₄

8 0
4 years ago
Read 2 more answers
5. Write a net ionic equation that occurs in a Na2HPO4/NaH2PO4 buffer solution when: A) a small amount of HCl is added (2 points
labwork [276]

Answer: (A) H_{3}O^{+}(aq) + HPO^{2-}_{4}(aq) \rightarrow H_{2}PO^{2-}_{4}(aq) + H_{2}O(l)

(B) H_{2}PO^{-}_{4}(aq) + OH^{-}(aq) \rightarrow HPO^{2-}_{4}(aq) + H_{2}O(l)

Explanation:

(A) As we know that HCl is a strong acid and when it is added to an aqueous solution then it leads to increase in the concentration of hydrogen ions. And, when an acid or base is added to a solution then any resistance by the solution in changing the pH of the solution is known as a buffer.

This means that addition of buffer into the given solution will not cause much change in the concentration of H_{3}O^{+} in large amount.

As both the buffer components are salt then they will remain dissociated as follows.

       Na_{2}HPO_{4}(aq) \rightarrow 2Na^{+}(aq) + HPO^{2-}_{4}(aq)

 NaH_{2}PO_{4}(aq) \rightarrow Na^{+}(aq) + H_{2}PO^{-}_{4}(aq)

Hence, net ionic equation will be as follows.

       H_{3}O^{+}(aq) + HPO^{2-}_{4}(aq) \rightarrow H_{2}PO^{2-}_{4}(aq) + H_{2}O(l)

(B)  When we add small amount of sodium hydroxide into the solution then there will occur an increase in concentration of hydroxide ions into the solution. But then due to the presence of buffer there will occur not much change in concentration and the acid will get converted into salt.

     NaOH(aq) \rightarrow Na^{+}(aq) + OH^{-}(aq)

The net ionic equation is as follows.

        H_{2}PO^{-}_{4}(aq) + OH^{-}(aq) \rightarrow HPO^{2-}_{4}(aq) + H_{2}O(l)

7 0
3 years ago
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