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Answer:
C₂ = 0.056 ppm
Explanation:
Given data:
Initial volume = 2.0 mL
Initial concentration = 7.0 ppm
Final volume = 250.0 mL
Final concentration = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Initial concentration
V₁ = Initial volume
C₂ = Final concentration
V₂ = Final volume
Now we will put the values in formula.
C₁V₁ = C₂V₂
7.0 ppm × 2.0 mL = C₂ × 250.0 mL
C₂ = 14.0 ppm.mL /250.0 mL
C₂ = 0.056 ppm
The unethical part about the mice's treatment is that John's classmates are taping on the glass and teasing the mice.
The number of sigma and pi bonds are,
Sigma Bonds =
16 Pi Bonds =
3Explanation: Every first bond formed between two atoms is sigma. Pi bond is formed when already a sigma bond is there. While in case of Alkyne (triple Bond) there is one sigma and one pi bond already present, so the third bond is formed by second side-to-side overlap of orbitals, hence, a second pi bond is formed.
Below all black bonds are sigma bonds, while in alkene there is one pi bond and in alkyne there are two pi bonds.
Answer:
As shown in the attachment.
Explanation:
In this case, there are two isomers possible. Isomers are compounds that have the same molecular formular but different structural formular.
Considering the hydrocarbon C8H10, which has 8C expected saturated hydrocarbon. however when there is an excess of 8H, we have C8H18 which is the formular of octane, a member of the alkane family and from monosubstitution reaction which involves reaction with halogens (particularly Chlorine), the reaction will be a repeated substitution reaction where chlorine will be replaced with each of the hydrogen.