The answer is “B” because if you do the work correctly that will be your outcome
Answer:
Therefore the ball strikes the ground 5.98 s after kick.
Step-by-step explanation:
Given that , a ball is kicked in the air. The height of the ball can be calculated using the equation 
where h is height in feet and t is time in second.
When the ball touches the ground then the height will be zero.
i.e h(t)=0
Therefore
Since -2≠0 then 
[The solution of a quadratic equation ax²+bx+c=0 is
here a=8, b=-32 and c=-95]
![\Rightarrow t =\frac{-(-32)\pm\sqrt{(-32)^2-[4\times8\times(-95)]} }{2\times8}](https://tex.z-dn.net/?f=%5CRightarrow%20t%20%3D%5Cfrac%7B-%28-32%29%5Cpm%5Csqrt%7B%28-32%29%5E2-%5B4%5Ctimes8%5Ctimes%28-95%29%5D%7D%20%7D%7B2%5Ctimes8%7D)
Therefore t= 5.98 or -1.98
since time can not be negative So , t=5.98 s
Therefore the ball strikes the ground 5.98 s after kick.
There are approximately 8 ounces (7.901) in 224 grams.
The answer is true! Good luck!
To complete this equation, it is vital to know the slope. To find the slope using points, you subtract the first x from the second, and the first y from the second. This gives you a slope of 4. Then, you must follow point-slope form and choose one of the order pairs to use. You then write y then the negative of your number. Since the number is already negative, you turn it into a positive. On the other side of the "=" sign, you write your slope, 4 distributing to x. Then you write the negative of your x value. Since it is already negative, it turns into a positive. This gives you a final answer of y+1=4(x+2). I realize that this doesn't line up with your fill-in-the-blank answer, so I am sorry if it doesn't work.
