What is avogadros number

1. It depends what type of method you are using. if it is Height x Width x Length then it will not work for an irregular shape because it has extra pieces that would not be included.

2. The second method would work for both regular and irregular shapes because you would have to know or find out the volume of the regular shape to get the volume for the irregular shape.

3. It also depends on what you are doing, if you are doing a regular shape then use the first method, if it's an irregular shape then use the second method, if you do the maths correctly both should give you an accurate answer for what you want to achieve.

4. No, because the sugar would dissolve.

5. No, on this case the displacement method would not work because of the weight difference

Explanation:

All the answers for you!

4 0

3 years ago

Which of these is an environmental effect of building dams?

nadezda [96]

Hmm... I'm unsure but its either B or D.

7 0

3 years ago

Read 2 more answers

Suppose that 0.410 mol of methane, CH4(g), is reacted with 0.560 mol of fluorine, F2(g), forming CF4(g) and HF(g) as sole produc

Ber [7]

Answer:

The balanced equation for this reaction will be

$CH4 + 4F2$ → $CF4 + 4HF$

We can see that 1 mole of methane requires 4 moles of fluorine but we have 0.41 moles of CH4 and 0.56mole of F2

So using the unitary method we will get that

1 mole of CH4 → 4 mole of 4 mole of fluorine

0.41 mole of methane → 4*0.41 = 1.64 mole of fluorine for complete reaction

but we have only 0.56 mole of fluorine that means fluorine is the limiting reagent and the product will only be formed by only this amount of fluorine.

4 moles of fluorine → 1 mole of CF4

0.56 mole → $\frac{1}{4} * 0.56$ = 0.14mole of CF4

4 moles of fluorine → 4 moles of HF

0.56 mole of fluorine → 0.56 mole of HF

now to find the heat released we have the formula as

DELTA H = n * Delta H of product - n *delta H of reactant

where n is the moles of the reactant and product.

note: since no information is given about the enthalpies of the species we leave it on general equation also you need to add the product side enthalpy of the species present and similarly on the product side.

8 0

3 years ago