Find the leading coefficient and write the factored form of the function of least degree for the polynomial in the graph below.

The graph models the function y = −x2 − x + 6. Which attribute(s) of the graph tell you the root(s) of the function? Determine t

Alex73 [517]

In a graph the roots of the function are given by the cut points with the x axis.
On the other hand, we have the following equation:
y = -x2 - x + 6
To find the roots, we equate to zero:
-x2 - x + 6 = 0
Rewriting we have:
x2 + x - 6 = 0
(x-2) (x + 3) = 0
The roots are:
x1 = 2
x2 = -3
Answer:
The roots are:
x1 = 2
x2 = -3

7 0

2 years ago

Read 2 more answers

What happens to the value of the expression 2t/t as t decreases

anyanavicka [17]

Answer:

it stays the same until t=0, where it is undefined

Step-by-step explanation:

2t/t = 2 . . . . when t ≠ 0

2t/t = undefined when t = 0.

The value of t can increase or decrease and the value of the ratio remains the same. The value has a "hole" at t=0, where it is undefined. Otherwise, its value is always 2.

5 0

3 years ago

Plsss helppppppp plsssss

MrRa [10]

Set up an equation of ratios as shown below:

h 24 ft 4
----- = ---------- = ---
4 6 ft 1

Cross multiplying the 1st and 3rd fractions, we get h=16 ft (answer)

3 0

3 years ago

Draw a line plot for the fallowing data measured in inches

sladkih [1.3K]

Here you go I hope I helped

4 0

3 years ago

Eric was rock climbing. At one point, he stopped and climbed straight down 2\dfrac{1}{2}2

nikitadnepr [17]

The equation that matches the given situation is $-2\frac{1}{2}+6\frac{3}{4}=?$ . So, after two moves, Eric's elevation changed $4\frac{1}{4}$ meters above.

We know that in mathematics, subtraction means removing something from a group or a number of things. What is left in the group gets smaller when we subtract. The minuend is the first element we use. The subtrahend is the part that is being removed. The difference is the portion that remains after subtraction.

Assume that "negative" means climbing down and "positive" means climbing up. We must locate the elevation change in this area.

Given that Eric climbed straight down $2\frac{1}{2}$ meters. So we can write $-2\frac{1}{2}$ .

Again Eric climbed straight up $6\frac{3}{4}$ meters. So, we can write $6\frac{3}{4}$ .

Then the change = $-2\frac{1}{2}+6\frac{3}{4}$

= $-\frac{(2*2+1)}{2}+\frac{6*4+3}{4}$

= $-\frac{5}{2} +\frac{27}{4}$

= $\frac{-(5*2)+27}{4}$

= $\frac{-10+27}{4}$

= $\frac{17}{4}$

= $\frac{4*4+1}{4}$

= $4\frac{1}{4}$

Therefore, the equation that matches the given situation is $-2\frac{1}{2}+6\frac{3}{4}=?$ . So, after two moves, Eric's elevation changed $4\frac{1}{4}$ meters above.

Learn more about subtraction here -

brainly.com/question/24116578

#SPJ10

7 0

1 year ago