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3 years ago

PLEASE HELP! PLEASE HELP! PLEASE HELP

Mathematics

1 answer:

marin [14]3 years ago

4 0

1Distributive
2Commutative
3Associative
4Commutative
5Associative

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Solve for x in the equation X2-4x-9 = 29 X = 2+ 42 X = 2+ V33 X= 2+ 34 X=442

tester [92]

Answer: A) x=2±V42

(Random text)

4 0

4 years ago

In 1990, 23.8% of 18-24 year-olds in Biddeford, Maine were attending college. About 10 years later, a random sample of 610 18-24

Vlada [557]

Answer:

There is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 610

p = 23.8% = 0.238

Alpha, α = 0.01

Number of 18-24 year-old attending college , x = 178

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.238\\H_A: p > 0.238$

This is a one-tailed(right) test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{178}{610} = 0.2918$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.2918-0.238}{\sqrt{\frac{0.238(1-0.238)}{610}}} = 3.1201$

Now, we calculate the p-value from the table.

P-value = 0.0009

Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject the null hypothesis.

Conclusion:

Thus there is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

4 0

4 years ago

Read 2 more answers

-3n-5 , please help

Mila [183]

Answer:

(0,-5)

Step-by-step explanation:

3 0

4 years ago

o bill customers for water usage, one city converts the number of gallons used into units. This relationship is represented by t

nlexa [21]

G = 748u

g is the dependent variable....true
u is the independent variable....true

8 0

3 years ago

Read 2 more answers

When a gas is kept at a constant temperature and pressure on it changes, its volume changes according to the following formula,

astra-53 [7]

Answer: Approximately 1.9 atm

============================================

Work Shown:

$P_1*V_1 = P_2*V_2 \ \text{ ... Boyle's Law}\\\\4.5*1.5 = P_2*3.5\\\\6.75 = P_2*3.5\\\\P_2*3.5 = 6.75\\\\P_2 = \frac{6.75}{3.5}\\\\P_2 \approx 1.92857142857142\\\\P_2 \approx 1.9\\\\$

If the volume is 3.5 liters, then the pressure is approximately 1.9 atm.

Note the increase in volume leads to the reduction of pressure, and vice versa. The two variables have an inverse relationship.

-----------

As a check,

$P_1*V_1 = P_2*V_2\\\\4.5*1.5 \approx 1.9*3.5\\\\6.75 \approx 6.65\\\\$

We don't get the exact thing on both sides, but the two sides are close enough. We have rounding error due to P2 being not exact.

A more accurate check could be

$P_1*V_1 = P_2*V_2\\\\4.5*1.5 \approx 1.92857*3.5\\\\6.75 \approx 6.749995\\\\$

which has the two sides much closer to one another. This helps us verify the answer.

5 0

3 years ago