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Nataly [62]
3 years ago
12

Solve the system of equations -x - 2y = 11 and -3x - 2y = -7

Mathematics
1 answer:
rjkz [21]3 years ago
4 0
Answer: (9,-10) or x=9...y=-10
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Please help and explain all the way
Nesterboy [21]

Answer:

1.4 oz

Step-by-step explanation:

you know 3.5oz is 2.5 servings and you need to know what one is

3.5/2.5 = 1.4

one serving is 1.4

check -> 1.4 x 2.5= 3.5

4 0
3 years ago
A forestry company hopes to generate credits from the carbon sequestered in its plantations.The equation describing the forest w
Dmitry [639]

Answer:

Explanation:

Given:

The equation describing the forest wood biomass per hectare as a function of plantation age t is:

y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

The equation that describes the annual growth in wood biomass is:

y ′ (t) = 0.01t + 0.072t^2 - 0.018t^3

To find:

a) The year the annual growth achieved its highest possible value

b) when does y ′ (t) achieve its highest value?

a)

To determine the year the highest possible value was achieved, we will set the derivative y'(t) to zero. The values of t will be substituted into the second derivative to get the highest value

\begin{gathered} 0\text{ = 0.01t + 0.072t}^2\text{ - 0.018t}^3 \\ using\text{ a graphing tool,} \\ t\text{  = -0.1343} \\ \text{t = 0} \\ t\text{ = 4.1343} \\  \\ Since\text{ we can't have time as a negative value, t = 0 or t = 4.1343} \end{gathered}\begin{gathered} To\text{ ascertain which is the maximum, we take a second derivative} \\ y^{\prime}\text{'\lparen t\rparen = 0.01 + 0.144t - 0.054t}^2 \\  \\ substitute\text{ t = 0 and t = 4.13 respectively} \\ when\text{ t = 0 } \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen0\rparen - 0.054\lparen0\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0 - 0} \\ y^{\prime}\text{'\lparen t\rparen= 0.01 > 0} \\  \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen4.13\rparen - 0.054\lparen4.13\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= -0.316 < 0} \\  \\ if\text{ }y^{\prime}\text{'\lparen t\rparen > 0 , then it is minimum, } \\ if\text{ }y^{\prime}\text{'\lparen t\rparen < 0, then it is maximum} \end{gathered}

SInce t = 4.13, gives y ′' (t) = -0.316 (< 0). This makes it the maximum value of t

The year the annual growth achieved its highest possible value to the nearest whole number will be

year 4

b) y ′ (t) will achieve its highest value, when we substitute the value of t that gives into the initial function.

Initial function: y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

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6 0
1 year ago
I need help please with this question!!
Ira Lisetskai [31]
Sorry but where is the question
8 0
2 years ago
H(x)= -x^2 - 4<br> i(x)=2x+3<br><br> h(i(5))
pshichka [43]
H(x) = -x² - 4
i(x) = 2x + 3

h(i(5)) = -(2(5) + 3) - 4
h(i(5)) = -(10 + 3) - 4
h(i(5)) = -(13) - 4
h(i(5)) = -13 - 4
h(i(5)) = -17
6 0
3 years ago
​A person overcharges his bank account by spending the same amount of money each day. After five days of overcharging his bank a
sammy [17]

Answer:

20

Step-by-step explanation:

Why? because 100$ in 5 days is he spent the same much each day then it's 20 because 20 x 5=100

20 x 1=20

20 x 2=40

20 x 3=60

20 x 4=80

20 x 5=100

5 0
2 years ago
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