Answer:
Step-by-step explanation:
Let
Full time rates-$275, Part-time rates-$140
The problem can be expressed as:
Express eqtn1 in terms of f,
Substitute f value in eqtn 2.
Therefore, jeds has 17 fulltime and 9 parttime employees.
A linear approximation to the error in volume can be written as
... ∆V = (∂V/∂d)·∆d + (∂V/∂h)·∆h
For V=(π/4)·d²·h, this is
... ∆V = 2·(π/4)·d·h·∆d + (π/4)·d²·∆h
Using ∆d = 0.05d and ∆h = 0.05h, this becomes
... ∆V = (π/4)·d²·h·(2·0.05 + 0.05) = 0.15·V
The nominal volume is
... V = (π/4)·d²·h = (π/4)·(2.2 m)²·(6.8 m) = 25.849 m³
Then the maximum error in volume is
... 0.15V = 0.15·25.849 m³ ≈ 3.877 m³
_____
Essentially, the error percentage is multiplied by the exponent of the associated variable. Then these products are added to get the maximum error percentage.
Always start with what’s in the parentheses:)
Answer: 21 people voted
Step-by-step explanation:
an easy way to do this is simply multiply 84 * 0.25.
This gives you 
of the original amount
in this case 84×0.25 = 21
This means that 21 people voted
A direct variation has a constant slope, i.e. (y/x)= constant.
Both of the given two points give a slope of (y/x)=14/2=28/4=7, so the equation of the function is
y/x=7, or simply
y=7x
