Answer:

Step-by-step explanation:
Let

Full time rates-$275, Part-time rates-$140
The problem can be expressed as:

Express eqtn1 in terms of f,
Substitute f value in eqtn 2.

Therefore, jeds has 17 fulltime and 9 parttime employees.
A linear approximation to the error in volume can be written as
... ∆V = (∂V/∂d)·∆d + (∂V/∂h)·∆h
For V=(π/4)·d²·h, this is
... ∆V = 2·(π/4)·d·h·∆d + (π/4)·d²·∆h
Using ∆d = 0.05d and ∆h = 0.05h, this becomes
... ∆V = (π/4)·d²·h·(2·0.05 + 0.05) = 0.15·V
The nominal volume is
... V = (π/4)·d²·h = (π/4)·(2.2 m)²·(6.8 m) = 25.849 m³
Then the maximum error in volume is
... 0.15V = 0.15·25.849 m³ ≈ 3.877 m³
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Essentially, the error percentage is multiplied by the exponent of the associated variable. Then these products are added to get the maximum error percentage.
Always start with what’s in the parentheses:)
Answer: 21 people voted
Step-by-step explanation:
an easy way to do this is simply multiply 84 * 0.25.
This gives you
of the original amount
in this case 84×0.25 = 21
This means that 21 people voted
A direct variation has a constant slope, i.e. (y/x)= constant.
Both of the given two points give a slope of (y/x)=14/2=28/4=7, so the equation of the function is
y/x=7, or simply
y=7x