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Setler [38]
3 years ago
15

10r-60=9r solve for r​

Mathematics
2 answers:
GarryVolchara [31]3 years ago
6 0
The answer is R=60... yu have to subtract 10r from both sides which then leaves you with -60=-1r. From that, you divide both sides by -1 which ends to giving your answer which is r=60
PIT_PIT [208]3 years ago
6 0

Answer:

r = 60

Step-by-step explanation:

With any equation with a variable, you want to isolate the variable to find its actual value. I'll show you a step by step:

10r - 60 = 9r

Subtract 9r from both sides:

10r - 9r - 60 = 9r - 9r

Simplify:

r - 60 = 0

Add 60 to both sides to isolate r:

r - 60 + 60 = 0 + 60

Simplify:

r = 60

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Rina8888 [55]

Answer:

a) The general solution   θ = nπ±π/6

The all solutions are  - π/6 ,π/6 ,5π/6 ,7π/6 ,11π/6 ,13π/6 ...…

b)   The solutions in the interval [ 0,2π)

                            θ =  - π/6 ,π/6 , 5π/6 , 7π/6 , 11π/6

Step-by-step explanation:

<u><em>Step( i)</em></u>:-

Given an equation 2 cos (2θ)-1 =0

                               2 cos (2θ) = 1

                                cos(2θ) = 1/2

                                cos(2θ) = cos (π/3)

<em>Step(ii):-</em>

<em>a) </em>

The general solution of  cos θ = cos ∝ is given by

                                              θ = 2nπ±∝

The general solution of  cos(2θ) = cos (π/3) is

                                               2θ = 2nπ±π/3

                                                θ = nπ±π/6

Put n=0          θ =  ±π/6

Put n =1          θ = π±π/6

                       θ = π-π/6 = 5π/6

                        θ = π+π/6 = 7π/6

put n =2

                        θ = 2π±π/6  

                         θ = 2π-π/6 = 11π/6

                        θ = 2π+π/6 = 13π/6

   

The all solutions are  - π/6 ,π/6 ,5π/6 ,7π/6 ,11π/6 ,13π/6 ...…

b)

        The solutions in the interval [ 0,2π)

                            θ =  - π/6 ,π/6 , 5π/6 , 7π/6 , 11π/6

<u><em>Final answer</em></u>:-

a)

The all solutions are  - π/6 ,π/6 ,5π/6 ,7π/6 ,11π/6 ,13π/6 ...…

b)

The solutions in the interval [ 0,2π)

                            θ =  - π/6 ,π/6 , 5π/6 , 7π/6 , 11π/6

             

                                               

                                         

8 0
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zvonat [6]

Complete question is;

It took Priya 5 minutes to fill a cooler with 8 gallons of water from a faucet that was flowing at a steady rate. Let w be the number of gallons of water in the cooler after t minutes. Which of the following equations represent the relationship between w and t? Select all that apply

A) w = 1.6t

B) w = 0.625t

C) t = 1.6w

D) t = 0.625w

Answer:

Option A: w = 1.6t

& Option D: t = 0.625w

Step-by-step explanation:

We are told It took Priya 5 minutes to fill a cooler with 8 gallons of water at a steady rate.

Thus;

Rate of filling = 8 gallons/5 minutes = 1.6 gallons/minutes

Now, we are told that w is the number of gallons of water in the cooler after t minutes.

Thus, to find w, we will multiply the rate by t minutes.

w = 1.6 gallons/minutes × t minutes

w = 1.6t gallons

Or we can write as;

w/1.6 = t gallons

0.625w = t gallons

Therefore, options A & D are correct.

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