It is A I hope that helps for you
H(-6) = 2(-6) + 5
h(-6) = -12 + 5
Solution: h(-6) = -7
(2x - 3y) (4x - y) = 8x² - 2xy - 12xy + 3y²
(2x - 3y) (4x - y) = 8x² -14xy + 3y²
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Answer:8x² -14xy + 3y²
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Answer:
area ≈ 6.3 units²
Step-by-step explanation:
Calculate the area (A ) of the sector as
A = area of circle × fraction of circle
= πr² × 
= π × 4² × 
= 16π ×
← cancel 8 and 16 by 8, leaving
A = 2π ≈ 6.3 units² ( to 1 dec. place )