For this case what we have to take into account is the following variable:
x = represent the unknown number
We now write the following inequality:
"four times the sum of number and 15 is at least 20"
4 (x + 15)> = 20
We clear the value of x:
(x + 15)> = 20/4
(x + 15)> = 5
x> = 5 - 15
x> = - 10
The solution set is:
[-10, inf)
Answer:
all possible values for X are:
[-10, inf)
Answer:
13 students
Step-by-step explanation:
4 plus 9 = 13
We can one theorem to help us find rational roots of this polynomial.
2x^3 + x^2 - 4x - 2
We'll use Descartes' rule of signs.
Because there is 1 sign change, 1 of the 3 roots will be positive.
Now we can make the value of x -1 to see how many negative roots there will be.
-2 + 1 + 4 - 2
There are 2 sign changes, so we know there will be 2 negative roots.
Because of this, we should have 3 real, rational roots.
Answer:
The answer is True.
Step-by-step explanation:
-3x - 10 > -31
-3(5) - 10 > -31
-15 - 10 > -31
-25 > -31
True.
4/10 would be left you would make it a whole fraction at 10/10 then minus 4/10 and minus 2/10 that leaves 4/10 of cards. Hope this helps you out.
