The correct answer is (C)!
Since the area of the circle is 400π, 150π/400π = 135/360.
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
97
Step-by-step explanation:
<u>97 </u>+ 95 + 86 + 82 = 360
360 / 4 = <em>90</em>
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i hope this helps :))
Here for 120, the expression for the start root and end root is given
<h3>What will be the expression for start root and enroot of 120?</h3>
Here we need to find 
By simplifying the given expression, we get:
by taking square roots on both sides we get
Thus for 120, the expression for the start root and end root is given
To know more about the Square roots follow
brainly.com/question/124481
