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wariber [46]
3 years ago
6

3) Complete the square and write the following in Vertex Form. x2 - 8x + 12

Mathematics
1 answer:
Kitty [74]3 years ago
7 0
(x-6)(x-2) hope this helps
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Lori solved this multiplication problem.
Afina-wow [57]
A . Regroup the 2 in the tens column
6 0
3 years ago
Read 2 more answers
Please help me with 5-7
mixer [17]
2y+12 < 42

subtract 12 from both sides to isolate the 'y'

2y<30

since '2y' is multiplication, the opposite is division. divide by 2 to isolate the 'y'. doing so will flip the < sign to make it >.

y > 15

------------------------------------------------

She makes $15 an hour. Her employers take out $125 weekly. She gets a paycheck for $205 that week.

Add the $125 back in that her employer took out and you can find how much she earned that week, it's $330. Divide $330 by $15 to find that she worked a minimum of 22 hours that week.

15h-125=205

15h=330

h=22

plug 22 in to the equation 15h-125=205 to check your answer
------------------------------------------

I can't help you with the last one. Best of luck though man and god bless.


8 0
4 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
PLEASE HELP!!!!!!!!! ​
Ksju [112]

Answer:

C. Graph C :)

Step-by-step explanation:

6 0
3 years ago
- ( x - 1 ) = -4x - 2
7nadin3 [17]

Answer:

x=-1

Step-by-step explanation:

1. Remove the parenthesis

   -x + 1 = -4x - 2

2. Get x alone

  -x + 1 = -4x - 2

  +1x        +1x

1=-3x - 2

+2      +2

3=-3x          -3x/-3= x      3/-3 = -1      

x=-1

3 0
3 years ago
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