Answer:
I dunno this one, u should
Step-by-step explanation:
We need to compute the diagonal of yhe square.
d²=7²+7²=49×2cm²
d=7×sqrt(2)=7×1.41=9.87cm.
The diagonal we just computed is the diameter of the circle that contains the square.
Since d=9.87 < 11, then indeed, the square fits inside the circle, without touching it.
Answer:
There are no choices, but 
can be changes in the following ways: multiplying the numerator and the denominator by the same amount, or dividing the numerator and denominator by the same amount.
Hope it helps <3
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