Question

Complete the table of values for y= x^2-2x-3

Answer 1

Answer:

Anyone know the answer????????

Step-by-step explanation:

Answer 2

Answer:

x=3,y=0

x=-1,y=0

Step-by-step explanation:

We will have to factorise to get the value of x before solving for y

Let's solve

y=x^2-2x-3

To factorise x

x^2-3x+x-3

x(x-3)+1(x-3)

(x-3)+(x+1)

x-3=0

x=3

x+1=0

x=-1

Let's substitute the value of value to get the value for y

y=x^2-2x-3

When x is 3

y=3^2-2(3)-3

y=9-6-3

y=0

When x is-1

y=(-1)^2-2(-1)-3

y=1+2-3

y=0

Therefore when x is 3,y is 0

When x is -1,y is 0