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Ostrovityanka [42]
3 years ago
6

Indicate the general rule for the arithmetic sequence with a3 = -4 and a8 = -29.

Mathematics
1 answer:
solmaris [256]3 years ago
5 0
The general rule would be

a_n=6-5(n-1)

We first find the common difference, the value that is added every time to find the next term.  This is the same as the slope; the formula for slope is

m=(y₂-y₁)/(x₂-x₁)

Letting x be the term number and y be the term value, we have
m=(-29--4)/(8-3) = (-29+4)/(8-3) = -25/5 = -5

Now we work backwards from a₃ to find a₁, the first term.  We know that the common difference is -5; that means each time, the next term is found by subtracting 5.  If we want to work backward we will add 5:
-4+5=1 for a₂
1+5=6 for a₁

Now we can write the general form:
a_n=6-5(n-1)
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5 0
3 years ago
Read 2 more answers
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Calculator
mixas84 [53]

\text{Given : Which ordered pair is the solution to the system of equations?} \\  \\  \begin{cases}-5x - 3y = 12 \\   y - x = 12 \end{cases}

\text{Solution : According to the question, here let's take these variables as two}  \\  \text{equations then get their value and finally get the answer.} \\  \\  \sf  {1}^{st} \: equation  :  \\ \leadsto \frak{-5x - 3y = 12} \\  \\ \leadsto \frak{-5x = 12 + 3y} \\  \\ \leadsto \frak{x=  \frac{12 + 3y}{-5}} \qquad  \sf ...eq(1) \\  \\  \sf 2^{nd}  \: equation :  \\  \leadsto \frak{y = x - 12} \qquad \sf ...eq(2) \\  \\  \underline{  \frak{finding \: x  }} :  \\  \\  \dashrightarrow \frak{x=  \frac{12 + 3y}{-5}}  \\  \\ \dashrightarrow \frak{x=  \frac{12 + 3(x - 12)}{-5}}  \\  \\  \dashrightarrow \frak{x=  \frac{12 + 3x - 36}{-5}}  \\  \\  \dashrightarrow \frak{-5x=  12 + 3x - 36}  \\  \\  \dashrightarrow \frak{-5x - 3x=   - 24}  \\  \\  \dashrightarrow \frak{-8x =  - 24}  \\  \\  \star \quad \underline{ \boxed{ \green{ \frak{x =  3}}}} \\  \\ \underline{ \frak{ getting \: y}} : \\  \\  \dashrightarrow \frak{y = 3 - 12} \\  \\ \star  \quad\underline{  \boxed{\blue{ \frak{y =  - 9}}}} \\  \\

\green{ \mathbb{HENCEFORTH, \:  THE \:  PAIR \:  IS \:   \pink{\frak{ (3,-9)}}}}

5 0
3 years ago
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