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scoundrel [369]
3 years ago
8

Three green jelly bean, five red jelly beans and two orange jelly bean are in a bag.

Mathematics
2 answers:
IrinaVladis [17]3 years ago
7 0

Answer:

3/50

Step-by-step explanation:

3 g, 5 r, 2 o

3 + 5 + 2 = 10

Orange = 2 jelly beans

Probability of selecting an orange jelly bean: 2/10 or 1/5

If you put the jelly bean back in, there is still 10 jelly beans.

Green = 3 jelly beans

Probability of selecting a green jelly bean: 3/10

Multiply the probabilities:

1/5 x 3/10

= 3/50

Kruka [31]3 years ago
3 0
Hey can you help me with my physics work? i think my questions are getting ignored...
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A student union cafeteria worker checked the weight of ten half-pound bags of whole bean coffee and recorded the following weigh
Likurg_2 [28]

Answer: σ = 0.0154

Step-by-step explanation:

1. Calculate the mean for the recorded data.

(0.48 + 0.51 + 0.47 + 0.49 + 0.49 + 0.50 + 0.52 + 0.48 + 0.49 + 0.51)/10 =

4.94 / 10 = 0.49

The mean is represented with the greek letter μ, so μ = 0.49

2. For each element in the serie, subtract the mean (0.49) and square the result

(0.48 - 0.49)^2 = (-0.01)^2 = 0.0001

(0.51 - 0.49)^2 = (0.02)^2 = 0.0004

(0.47 - 0.49)^2 = (-0.02)^2 = 0.0004

(0.49 - 0.49)^2 = 0

(0.49 - 0.49)^2 = 0

(0.50 - 0.49)^2 = (0.01)^2 = 0.0001

(0.52 - 0.49)^2 = (0.03)^2 = 0.0009

(0.48 - 0.49)^2 = (-0.01)^2 = 0.0001

(0.49 - 0.49)^2 = 0

(0.51 - 0.49)^2 = (0.02)^2 = 0.0004

So we get these results: 0.0001, 0.0004, 0.0004, 0, 0, 0.0001, 0.0009, 0.0001, 0, 0.0004

3. Now, we calculate the mean of these squared differences

(0.0001 + 0.0004 + 0.0004 + 0 + 0 + 0.0001 + 0.0009 + 0.0001 + 0 + 0.0004) / 10 =

(0.0024) / 10 = 0.00024

4. Now to get the standard deviation, we need to get the root of this last value (0.00024).

√(0.00024) = 0.0154

5. So that will be our standard deviation value:

σ = 0.0154

DONE!

7 0
3 years ago
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