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dlinn [17]
3 years ago
7

​ A wire service is also known as a ____.

Computers and Technology
1 answer:
charle [14.2K]3 years ago
4 0
The answer is C press agency
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What is the reason that a modern electron microscope (TEM) can resolve biological images to the subnanometer level, as opposed t
zhannawk [14.2K]

Answer:

The correct answer to the following question will be "The wavelengths of the electron beams are also much shorter or less than illumination and visible light".

Explanation:

TEM seems to be a methodology of microscopy during which a pulse of electrons is transferred to create the effect through some kind of microscope, could approach biological objects at the sub-nanometer standard, as related to hundreds of nano-meters for either the absolute best microscope with super-resolution.

Also because of the electron beam's distances, they are still much shorter or smaller than daylight and infrared light, meaning that biological objects and artifacts can be resolved.

6 0
3 years ago
How to create a comparator generic type in java.
KIM [24]

Answer:

public class Person {

//fields

private int id;

private String name;

private Payment pay;

//constructor

public Person(String name, int id,

int startSal, int startBon){

this.name = name;

this.id = id;

this.pay = new Payment(startSal, startBon);

}

//method get name

public String getName(){

return name;

}

//method get id

public int getId(){

return id;

}

//method get start salary

public int getStartSalary(){

return pay.startSalary;

}

//method get start bonus

public int getStartBonus(){

return pay.startBonus;

}

//inner payment class

private class Payment{

int startSalary;

int startBonus;

public Payment(int sal, int bon){

this.startSalary = sal;

this.startBonus = bon;

8 0
2 years ago
Write a script that calculates the common factors between 8 and 24. To find a common factor, you can use the modulo operator (%)
AnnyKZ [126]

Answer:

  1. common = []
  2. num1 = 8
  3. num2 = 24
  4. for i in range(1, num1 + 1):
  5.    if(num1 % i == 0 and num2 % i == 0):
  6.        common.append(i)
  7. print(common)

Explanation:

The solution is written in Python 3.

Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).

Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).

Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i  will be zero and the if block will run to append the current i value to common list (Line 6-8).

After the loop, print the common list and we shall get [1, 2, 4, 8]

8 0
3 years ago
Write one for loop to print out each element of the list several things. then write another for loop
Kay [80]

Question:

Write one for loop to print out each element of the list several_things. Then, write another for loop to print out the TYPE of each element of the list several_things.

Answer:

The solution in python is as follows:

for element in several_things:

    print(element)

   

for element in several_things:

    print(type(element))

Explanation:

The solution assumes that the list several_things has already been initialized.

So, the rest of the code is explained as follows:

This line iterates through the list, several_things

for element in several_things:

This line prints each element

    print(element)

This line iterates through the list, several_things for the second time    

for element in several_things:

This line prints the type of each element

    print(type(element))

6 0
2 years ago
A teacher has five students who have taken four tests. The teacher uses the following grading scale to assign a letter grade to
AlladinOne [14]

Answer:

#include <iostream>

using namespace std;

int main()

{

const int numofStudents = 5;//number of students

const int numofTests = 2;//number of tests taken by students

const int grade = 5;//number of grades available

char letter[grade] = { 'A','B','C','D','F' };

double table[numofStudents][numofTests];//defining 2darray with names and scores

string names[numofStudents];//storing names of students

for (int num = 0; num < numofStudents; num++)//storing names and scores of students

{

 cout << "Enter student's name: ";

 cin >> names[num];

 for (int test = 0; test < numofTests; test++)//scores loop

 {

  cout << "Enter the test score: ";

  cin >> table[num][test];

  if (table[num][test] < 0 || table[num][test]>100)//input validation

  {

   cout << "Invalid input. Try again" << endl;

   cin >> table[num][test];//input again

  }

 }

}

for (int i = 0;i < numofStudents;i++)//calculating averages and grades

{

 int sum = 0;

 cout << "Test scores for " << names[i] << ": " << endl;

 for (int j = 0;j < numofTests;j++)

 {

  cout << table[i][j] << " ";

  sum += table[i][j];//summing scores

 }

 cout << endl;

 float average = (float)sum / numofTests;//calculating the average

 cout << "Making an average of: "<< average;

 if (average <= 100 && average >= 90)//assigning a grade

 {

  cout << " and has received an " << letter[0];

 }

 else if (average <= 89 && average >= 80)

 {

  cout << " and has received a " << letter[1];

 }

 else if (average <= 79 && average >= 70)

 {

  cout << " and has received a " << letter[2];

 }

 else if (average <= 69 && average >= 60)

 {

  cout << " and has received a " << letter[3];

 }

 else if (average <= 59 && average >= 0)

 {

  cout << " and has received an " << letter[4];

 }

 else

 {

  cout << "Invalid scores entered." << endl;

 }

 cout << endl;

}

 return 0;

}

Explanation:

We first define the number of students, number of tests and number of grades available for assignments. We then fill in the 2D array of students names and their scores making sure assigning more than 100 and less than 0 is not allowed. We then sum the scores and retrieve an average. Using the average, a letter grade is assigned to that individual.

6 0
2 years ago
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