<u><em>Answer:</em></u>
108 square units
<h3><u><em>
Step-by-step explanation:</em></u></h3>
3 x 4 = 12
3 x 4 = 12
6 x 3 = 18
6 x 3 = 18
6 x 4 = 24
6 x 4 = 24
24(2) + 18(2) + 12(2) = 108 square units
Therefore, the surface area of the rectangular solid below using its net is <u>108 square units</u>
Answer:
a) θ =
b) r = 31.27 inch
Step-by-step explanation:
(a)
area of sector:
* r² * θ
384 =
* r² * θ
384 =
* (24)² * θ
θ = 384/288
θ = 
(b)
384 =
* r² * 
r² = 384 * 2 * 
r² = 977.848
r = √977.848
r = 31.27 inch
You could make a tree diagram
H T ← 1st toss
H T H T ← 2nd toss
H T H T H T H T ← 3rd toss
etc ,,, then count the combination of favorable outcomes
Using a calculator:
Total number of outcomes is

= 128
Probability of getting exactly 3 heads is found using the follow calculator feature: binompdf(7, 0.5, 3)
ANSWER: Typed into the calculator as follows binompdf(7,0.5,3)×128 =
35
We don't know what the exact p-value is, but we are told that it's as large as 0.005 which is smaller than alpha = 0.05
Since the p-value is smaller than alpha, this means we <u>reject the null hypothesis</u>.
The way you can remember this is "if the p-value is low, then the null must go". By "low", I mean "smaller than alpha".
Recall that the p-value is the probability of observing that specific test statistic, or larger. So the chances of chi-squared being 18.68 or larger is a probability between 0.0025 and 0.005; there's a very small chance of this happening. The p-value is based entirely on the assumption that the null is correct. But if the null is correct, then the chances of landing on this are very small. We have a contradiction that basically leads to us concluding the null must not be the case. It's not 100% guaranteed of course, but it's fairly strong evidence.
In short, the p-value being smaller than alpha = 0.05 means we reject the null.
In order to accept the null, the p-value must be 0.05 or larger.