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Ipatiy [6.2K]
3 years ago
6

If two lines are parallel, their slopes will be the same. The slope is represented by the m in y=mx+b

Mathematics
1 answer:
Georgia [21]3 years ago
3 0
This phrase is very true
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Given right triangle JKL, what is the value of cos(L)?
Daniel [21]

First option is correct.

Since we have given that

JKL is a right triangle.

Length of JK = 12

Length of KL = 5

By Pythagoras theorem, we get that

JL^{2}=JK^{2}+ KL^{2}\\JL^{2}=12^{2}+ 5^{2} \\JL^{2}=144+25= 169\\JL=13

So, cos (L) would be

cos(L)=base/hypotenuse

cos(L)=5/13

Hence, First option is correct.

learn more about Pythagoras theorem and cosine ratios here:

brainly.com/question/9027282

#SPJ1

6 0
1 year ago
How kany doulutions does this equation have 25 - 4x=15-3x+10-x
natima [27]
Since it's a one-variable equation, it has only one solution:

25 - 4x = 15 - 3x + 10 - x

25 - 4x + x = 15 - 3x + 10

25 - 3x = 15 - 3x + 10

- 3x = 15 - 3x + 10 - 25

- 3x = 15 - 3x - 15

- 3x + 3x = 15 - 15

0 = 15 - 15

0 = 0




Hope it helped,



BioTeacher101
4 0
3 years ago
What is 2/3 divided by 5
BARSIC [14]

Answer: Hey here’s your answer: 2/3 divided by 5=2/15

Hth

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
In 1985, the price of a gallon of milk cost about $2.20 per gallon. In 2005, the price of a gallon of milk cost about $3.50 per
Assoli18 [71]

the percent increase in the price of a gallon of milk from 1985 to 2005 is 59%

Define percent increase

Percent increase can be described as the rise in the value of an item, in this case the value is milk.

Write out the parameters

In 1985 the price of a gallon of milk is $2.20

In 2005 the price is $3.50

Formula for percent increase

new price-old price/new price × 100

Calculate the percent increase

new price= $3.50

old price= $2.20

= 3.50-2.20/2.20

= 1.3/2.20

= 0.59 × 100

= 59%

Hence the percent increase from 1985 t0 2005 is 59%

Please see the link below for more information

brainly.com/question/878172

6 0
2 years ago
The height of a cylinder is 18 cm. The area of the base of the cylinder is 25 ㎠. Find V.
IrinaVladis [17]
Its 150 cause V is 1/3*Area*height
4 0
3 years ago
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