Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q =
- 
= 0
Sum of angles in a triangle = 
<P + <Q + <S = 
048° + 0
+ <S = 
+ <S = 
<S =
- 
= 
<S = 
Applying the Sine rule,
=
= 
= 
= 
= 
⇒ y = 
= 12.703
y = 12.70 km
= 
= 
= 
⇒ x = 
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Answer:
28.3
Step-by-step explanation:
9x3.142=28.27800 and if you round that it is 28.3
7/10. Because 0.7 equals 70% . As a fraction it would be 70/100. Simplify, and you get 7/10.
<u>Answer:</u>
1/5
<u>Step-by-step explanation:</u>
To find this you would need to multiply the probability of pulling a white marble to the probability of pulling out a green marble.
1)First you would need the probability of pulling out a white marble. There are 10 marbles in total and out of those 2 are white. So the probability of pulling out a white marble would be 2/10. If you simplify that you would get 1/5 for the probability of pulling out a white marble.
2)Next, you would find the probability of pulling out a green marble. Using the same process that we used to find the probability of pulling out a white marble, we would find the answer to be 3/10. All that we did here was <em>green marbles/total marbles</em>. By filling that in we got 3/10 for the probability of pulling out a green marble.
3)Now all that is left is doing <em>probability of pulling a white marble × probability of pulling out a green marble</em>. This would be 1/5 × 3/10. After solving the answer would be 3/15 which we would simplify down to 1/5 as our final answer.
Answer:
The answer is 20 degrees
Step-by-step explanation:
A trapezoid is a quadrilateral with four angles and the sum of the four angles is 360 degrees.
Britton rotated the trapezoid ABCD 180º, but we were not told that he tampered with the angles size or shape, we can now agree that it is still the same trapezoid that was rotated without any alterations in angles, size and shape.
Since we've been given that the angle B is 20º, and the measurement was not altered when rotating the trapezoid. Therefore the angle B' will also be 20º.
I hope this helps.