Question

What are the roots of x2 + 10x + 29 = 0?

Answer 1

Answer:

The roots of the given equation are -5 + 2i and -5 - 2i

Step-by-step explanation:

Since, roots of an equation are the points which satisfy the equation,

Or the points which are obtained after solving the equation. ( by putting zero on right side )

Here, the given quadratic equation,

$x^2+10x+29=0$

If we have an equation, ax² +bx + c = 0

By quadratic formula,

$x=\frac{-b\pm \sqr{b^2-4ac}}{2a}$

By comparing,

The solution of the given equation is,

$x=\frac{-10\pm \sqrt{10^2-4\times 1\times 29}}{2\times 1}$

$x=\frac{-10\pm \sqrt{100-116}}{2}$

$x=\frac{-10\pm \sqrt{-16}}{2}$

$x=\frac{-10\pm +4i}{2}$

$\implies x = -5\pm 2i$

Thus, the roots of the given equation are -5 + 2i and -5 - 2i

Answer 2

X² + 10x + 29 = 0
x = -(10) ± √((10)² - 4(1)(29))
                       2(1)
x = -10 ± √(100 - 116)
                     2
x = -10 ± √(-16)
               2
x = -10 ± 4i
            2
x = -5 ± 2i
x = -5 + 2i    or    x = -5 - 2i

THe roots of the function is 5 ± 2i.